From 4f1c9a3c69d8519ad2905342fea61b51ce3f3d3e Mon Sep 17 00:00:00 2001
From: pvcfg6a7k <3378341862@qq.com>
Date: Wed, 26 Mar 2025 19:47:45 +0800
Subject: [PATCH] Update README.md

---
 README.md | 45 ++++++++++++++++++++++++++++++++++++++++++++-
 1 file changed, 44 insertions(+), 1 deletion(-)

diff --git a/README.md b/README.md
index 77f94c4..ef2a569 100644
--- a/README.md
+++ b/README.md
@@ -31,4 +31,47 @@ special
 1.安全性考虑
 2.通过用户借阅图书推测出用户喜好并推荐图书
 3.统计每种图书的借阅数量供下次买书参考
-4.是否需要对用户等级进行分类，比如借数超过50本还书时间限制延长一个周
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+4.是否需要对用户等级进行分类，比如借数超过50本还书时间限制延长一个周
+import tkinter as tk
+
+
+def find_user():
+ username = text_user.get()
+ password = text_password.get()
+
+ # 简单验证（仅作为示例）
+ if username and password:
+  result_label.config(text=f'谢谢, {username}!')
+ else:
+  result_label.config(text='请输入用户名和密码!')
+
+
+window = tk.Tk()
+window.title('图书管理系统')
+window.geometry('400x500')
+
+label_prompt = tk.Label(window, text='请输入您的用户名和密码', bg='green', font=('Arial', 12), width=20, height=2)
+label_prompt.pack(pady=10)
+
+frame_inputs = tk.Frame(window)
+frame_inputs.pack(pady=10)
+
+label_username = tk.Label(frame_inputs, text='用户名:', font=('Arial', 12))
+label_username.grid(row=0, column=0, padx=5, pady=5)
+
+text_user = tk.Entry(frame_inputs, font=('Arial', 12))
+text_user.grid(row=0, column=1, padx=5, pady=5)
+
+label_password = tk.Label(frame_inputs, text='密码:', font=('Arial', 12))
+label_password.grid(row=1, column=0, padx=5, pady=5)
+
+text_password = tk.Entry(frame_inputs, font=('Arial', 12), show='*')
+text_password.grid(row=1, column=1, padx=5, pady=5)
+
+button_confirm = tk.Button(window, text='确认', bg='green', width=15, height=2, command=find_user)
+button_confirm.pack(pady=20)
+
+result_label = tk.Label(window, text='', bg='green', font=('Arial', 12), width=20, height=2)
+result_label.pack(pady=10)
+
+window.mainloop()
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