Update 求斐波那契数列

master
pxecwsohz 4 years ago
parent 25dce8a1fd
commit 406acd42ee

@ -0,0 +1,19 @@
#include<stdio.h>
int Fibon1(int n)
{
if(n == 1||n == 2)
{
return 1;
}
else{
return Fibon1(n-1) + Fibon1(n-2);
}
}
int main()
{
int n,s;
scanf("%d",&n);
s = Fibon1(n);
printf("%d",s)
return 0;
}
Loading…
Cancel
Save