test(test): 添加测试用例

master
jing 6 days ago
parent e72944a36b
commit 1a5e05ea00

@ -91,7 +91,7 @@ cmake --build build -j "$(nproc)"
跑完整编译流程自检:从 SysY 源码生成 AArch64 汇编,完成汇编、链接,在 QEMU 下运行结果程序,并与 `test/test_case` 下同名 `.out` 自动比对:
```bash
./scripts/verify_asm.sh test/test_case/simple_add.sy test/test_result/asm --run
./scripts/verify_asm.sh test/test_case/function/simple_add.sy test/test_result/function/asm --run
```
如果最终看到 `输出匹配: test/test_case/simple_add.out`,说明当前示例用例 `return a + b` 的完整链路已经跑通。

@ -28,7 +28,7 @@ Lab1 聚焦前端第一步:词法/语法分析。
1. 主要覆盖 `int main() { ... }` 这一固定函数形态。
2. 只包含少量声明/返回/表达式能力(用于演示完整流程)。
3. 示例用例位于 `test/test_case/simple_add.sy`。
3. 示例用例位于 `test/test_case/function/simple_add.sy`。
## 5. 构建与生成流程
@ -68,7 +68,7 @@ cmake --build build -j "$(nproc)"
```bash
# 仅输出语法树
./build/bin/compiler --emit-parse-tree test/test_case/simple_add.sy
./build/bin/compiler --emit-parse-tree test/test_case/function/simple_add.sy
```
但最终不能只检查 `simple_add`。完成 Lab1 后,应至少对 `test/test_case` 下全部 `.sy` 用例逐个验证解析是否成功;如有需要,也可以自行编写批量测试脚本统一执行。

@ -49,20 +49,20 @@ cmake --build build -j "$(nproc)"
可先用单个样例检查 IR 输出是否基本正确:
```bash
./build/bin/compiler --emit-ir test/test_case/simple_add.sy
./build/bin/compiler --emit-ir test/test_case/function/simple_add.sy
```
如需打印语法树:
```bash
./build/bin/compiler --emit-parse-tree test/test_case/simple_add.sy
./build/bin/compiler --emit-parse-tree test/test_case/function/simple_add.sy
```
推荐使用统一脚本验证 “IR -> LLVM 后端 -> 可执行程序” 整体链路。`--run` 模式下会自动读取同名 `.in`,并将程序输出与退出码和同名 `.out` 比对,用于验证 IR 的正确性:
```bash
./scripts/verify_ir.sh test/test_case/simple_add.sy test/test_result/ir --run
./scripts/verify_ir.sh test/test_case/function/simple_add.sy test/test_result/function/ir --run
```
但最终不能只检查 `simple_add`。完成 Lab2 后,应对 `test/test_case` 下全部测试用例逐个回归,确认 IR 生成与 `--run` 链路都能通过;如有需要,也可以自行编写批量测试脚本统一执行。

@ -47,13 +47,13 @@ cmake --build build -j "$(nproc)"
可先用单个样例检查汇编输出是否基本正确:
```bash
./build/bin/compiler --emit-asm test/test_case/simple_add.sy
./build/bin/compiler --emit-asm test/test_case/function/simple_add.sy
```
推荐使用统一脚本验证 “源码 -> 汇编 -> 可执行程序” 整体链路。`--run` 模式下会自动读取同名 `.in`,并将程序输出与退出码和同名 `.out` 比对,用于验证后端代码生成的正确性:
```bash
./scripts/verify_asm.sh test/test_case/simple_add.sy test/test_result/asm --run
./scripts/verify_asm.sh test/test_case/function/simple_add.sy test/test_result/function/asm --run
```
若最终输出 `输出匹配: test/test_case/simple_add.out`,说明当前示例用例 `return a + b` 的完整后端链路已经跑通。

@ -79,13 +79,13 @@ cmake --build build -j "$(nproc)"
项目编译后可先用当前示例用例检查后端链路是否仍能运行:
```bash
./build/bin/compiler --emit-asm test/test_case/simple_add.sy
./build/bin/compiler --emit-asm test/test_case/function/simple_add.sy
```
推荐继续使用统一脚本验证 “源码 -> 汇编 -> 可执行程序” 整体链路。`--run` 模式下会自动读取同名 `.in`,并将程序输出与退出码和同名 `.out` 比对,用于检查单个用例的完整结果:
```bash
./scripts/verify_asm.sh test/test_case/simple_add.sy test/test_result/asm --run
./scripts/verify_asm.sh test/test_case/function/simple_add.sy test/test_result/function/asm --run
```
建议在功能回归之外,再观察优化前后汇编输出差异。可按自己的实现方式保留调试日志、优化开关,或直接对比生成的汇编文本,重点关注:

@ -95,7 +95,7 @@ cmake --build build -j "$(nproc)"
### 6.1 观察 IR
```bash
./build/bin/compiler --emit-ir test/test_case/simple_add.sy
./build/bin/compiler --emit-ir test/test_case/function/simple_add.sy
```
这条命令只适合先观察单个样例的 IR 形态。完成 Lab5 后,不能只检查 `simple_add`,还应覆盖 `test/test_case` 下全部测试用例。
@ -103,8 +103,8 @@ cmake --build build -j "$(nproc)"
### 6.2 语义回归
```bash
./scripts/verify_ir.sh test/test_case/simple_add.sy test/test_result/ir --run
./scripts/verify_asm.sh test/test_case/simple_add.sy test/test_result/asm --run
./scripts/verify_ir.sh test/test_case/function/simple_add.sy test/test_result/function/ir --run
./scripts/verify_asm.sh test/test_case/function/simple_add.sy test/test_result/function/asm --run
```
目标:脚本自动读取同名 `.in`,并将程序输出与退出码和同名 `.out` 比对,确保优化后程序行为与优化前保持一致。

@ -59,8 +59,8 @@ cmake --build build -j "$(nproc)"
### 7.1 功能回归
```bash
./scripts/verify_ir.sh test/test_case/simple_add.sy test/test_result/ir --run
./scripts/verify_asm.sh test/test_case/simple_add.sy test/test_result/asm --run
./scripts/verify_ir.sh test/test_case/function/simple_add.sy test/test_result/function/ir --run
./scripts/verify_asm.sh test/test_case/function/simple_add.sy test/test_result/function/asm --run
```
`--run` 模式下脚本会自动读取同名 `.in`,并将程序输出与退出码和同名 `.out` 比对。
@ -71,8 +71,8 @@ cmake --build build -j "$(nproc)"
```bash
# 对比优化前后 IR/汇编输出(按你实现的开关或日志方式执行)
./build/bin/compiler --emit-ir test/test_case/simple_add.sy
./build/bin/compiler --emit-asm test/test_case/simple_add.sy
./build/bin/compiler --emit-ir test/test_case/function/simple_add.sy
./build/bin/compiler --emit-asm test/test_case/function/simple_add.sy
```
这里的 `simple_add` 只用于展示如何观察单个样例的输出差异;实际评估优化效果时,仍应结合更多测试用例,必要时覆盖全部测试集。

@ -1,5 +1,5 @@
#!/usr/bin/env bash
# ./scripts/verify_ir.sh test/test_case/simple_add.sy --run
# ./scripts/verify_ir.sh test/test_case/function/simple_add.sy test/test_result/function/ir --run
set -euo pipefail

@ -62,5 +62,5 @@ void PrintHelp(std::ostream& os) {
<< " - 默认输出 IR\n"
<< " - 若使用 --emit-parse-tree/--emit-ir/--emit-asm则仅输出显式选择的阶段\n"
<< " - 可使用重定向写入文件:\n"
<< " compiler --emit-asm test/test_case/simple_add.sy > out.s\n";
<< " compiler --emit-asm test/test_case/function/simple_add.sy > out.s\n";
}

@ -1,5 +0,0 @@
110 70 30
278 174 70
446 278 110
614 382 150
0

@ -1,19 +0,0 @@
ok
ok
ok
ok
ok
ok
ok
ok
0x1.e691e6p+1 3
0x1.e691e6p+3 12
0x1.11b21p+5 28
0x1.e691e6p+5 50
0x1.7c21fcp+6 78
0x1.11b21p+7 113
0x1.7487b2p+7 153
0x1.e691e6p+7 201
0x1.33e85p+8 254
10: 0x1.333334p+0 0x1.333334p+1 0x1.ccccccp+1 0x1.333334p+2 0x1.8p+2 0x1.ccccccp+2 0x1.0cccccp+3 0x1.333334p+3 0x1.599998p+3 0x1p+0
0

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@ -0,0 +1,89 @@
const int N = 1024;
void mm(int n, int A[][N], int B[][N], int C[][N]){
int i, j, k;
i = 0; j = 0;
while (i < n){
j = 0;
while (j < n){
C[i][j] = 0;
j = j + 1;
}
i = i + 1;
}
i = 0; j = 0; k = 0;
while (k < n){
i = 0;
while (i < n){
if (A[i][k] == 0){
i = i + 1;
continue;
}
j = 0;
while (j < n){
C[i][j] = C[i][j] + A[i][k] * B[k][j];
j = j + 1;
}
i = i + 1;
}
k = k + 1;
}
}
int A[N][N];
int B[N][N];
int C[N][N];
int main(){
int n = getint();
int i, j;
i = 0;
j = 0;
while (i < n){
j = 0;
while (j < n){
A[i][j] = getint();
j = j + 1;
}
i = i + 1;
}
i = 0;
j = 0;
while (i < n){
j = 0;
while (j < n){
B[i][j] = getint();
j = j + 1;
}
i = i + 1;
}
starttime();
i = 0;
while (i < 5){
mm(n, A, B, C);
mm(n, A, C, B);
i = i + 1;
}
int ans = 0;
i = 0;
while (i < n){
j = 0;
while (j < n){
ans = ans + B[i][j];
j = j + 1;
}
i = i + 1;
}
stoptime();
putint(ans);
putch(10);
return 0;
}

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@ -0,0 +1,71 @@
int x;
const int N = 2010;
void mv(int n, int A[][N], int b[], int res[]){
int x, y;
y = 0;
x = 11;
int i, j;
i = 0;
while(i < n){
res[i] = 0;
i = i + 1;
}
i = 0;
j = 0;
while (i < n){
j = 0;
while (j < n){
if (A[i][j] == 0){
x = x * b[i] + b[j];
y = y - x;
}else{
res[i] = res[i] + A[i][j] * b[j];
}
j = j + 1;
}
i = i + 1;
}
}
int A[N][N];
int B[N];
int C[N];
int main(){
int n = getint();
int i, j;
i = 0;
while (i < n){
j = 0;
while (j < n){
A[i][j] = getint();
j = j + 1;
}
i = i + 1;
}
i = 0;
while (i < n){
B[i] = getint();
i = i + 1;
}
starttime();
i = 0;
while (i < 50){
mv(n, A, B, C);
mv(n, A, C, B);
i = i + 1;
}
stoptime();
putarray(n, C);
return 0;
}

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@ -0,0 +1,106 @@
const int base = 16;
int getMaxNum(int n, int arr[]){
int ret = 0;
int i = 0;
while (i < n){
if (arr[i] > ret) ret = arr[i];
i = i + 1;
}
return ret;
}
int getNumPos(int num, int pos){
int tmp = 1;
int i = 0;
while (i < pos){
num = num / base;
i = i + 1;
}
return num % base;
}
void radixSort(int bitround, int a[], int l, int r){
int head[base] = {};
int tail[base] = {};
int cnt[base] = {};
if (bitround == -1 || l + 1 >= r) return;
{
int i = l;
while (i < r){
cnt[getNumPos(a[i], bitround)]
= cnt[getNumPos(a[i], bitround)] + 1;
i = i + 1;
}
head[0] = l;
tail[0] = l + cnt[0];
i = 1;
while (i < base){
head[i] = tail[i - 1];
tail[i] = head[i] + cnt[i];
i = i + 1;
}
i = 0;
while (i < base){
while (head[i] < tail[i]){
int v = a[head[i]];
while (getNumPos(v, bitround) != i){
int t = v;
v = a[head[getNumPos(t, bitround)]];
a[head[getNumPos(t, bitround)]] = t;
head[getNumPos(t, bitround)] = head[getNumPos(t, bitround)] + 1;
}
a[head[i]] = v;
head[i] = head[i] + 1;
}
i = i + 1;
}
}
{
int i = l;
head[0] = l;
tail[0] = l + cnt[0];
i = 0;
while (i < base){
if (i > 0){
head[i] = tail[i - 1];
tail[i] = head[i] + cnt[i];
}
radixSort(bitround - 1, a, head[i], tail[i]);
i = i + 1;
}
}
return;
}
int a[30000010];
int ans;
int main(){
int n = getarray(a);
starttime();
radixSort(8, a, 0, n);
int i = 0;
while (i < n){
ans = ans + i * (a[i] % (2 + i));
i = i + 1;
}
if (ans < 0)
ans = -ans;
stoptime();
putint(ans);
putch(10);
return 0;
}

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@ -0,0 +1,110 @@
int A[1024][1024];
int B[1024][1024];
int C[1024][1024];
int main() {
int T = getint(); // 矩阵规模
int R = getint(); // 重复次数
int i = 0;
while (i < T) {
if (i < T / 2) {
getarray(A[i]);
}
i = i + 1;
}
i = 0;
while (i < T) {
if (i >= T / 2) {
getarray(B[i]);
}
i = i + 1;
}
starttime();
i = 0;
while (i < T) {
if (i >= T / 2) {
int j = 0;
while (j < T) {
A[i][j] = -1;
j = j + 1;
}
}
i = i + 1;
}
i = 0;
while (i < T) {
if (i < T / 2) {
int j = 0;
while (j < T) {
B[i][j] = -1;
j = j + 1;
}
}
i = i + 1;
}
i = 0;
while (i < T) {
int j = 0;
while (j < T) {
C[i][j] = A[i][j] * 2 + B[i][j] * 3;
j = j + 1;
}
i = i + 1;
}
i = 0;
while (i < T) {
int j = 0;
while (j < T) {
int val = C[i][j];
val = val * val + 7;
val = val / 3;
C[i][j] = val;
j = j + 1;
}
i = i + 1;
}
i = 0;
while (i < T) {
int j = 0;
while (j < T) {
int k = 0;
int sum = 0;
while (k < T) {
sum = sum + C[i][k] * A[k][j];
k = k + 1;
}
A[i][j] = sum;
j = j + 1;
}
i = i + 1;
}
int total = 0;
int r = 0;
while (r < R) {
i = 0;
while (i < T) {
int j = 0;
while (j < T) {
total = total + A[i][j] * A[i][j];
j = j + 1;
}
i = i + 1;
}
r = r + 1;
}
stoptime();
putint(total);
putch(10);
return 0;
}

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@ -0,0 +1,82 @@
const int mod = 998244353;
int d;
int multiply(int a, int b){
if (b == 0) return 0;
if (b == 1) return a % mod;
int cur = multiply(a, b/2);
cur = (cur + cur) % mod;
if (b % 2 == 1) return (cur + a) % mod;
else return cur;
}
int power(int a, int b){
if (b == 0) return 1;
int cur = power(a, b/2);
cur = multiply(cur, cur);
if (b % 2 == 1) return multiply(cur, a);
else return cur;
}
const int maxlen = 2097152;
int temp[maxlen], a[maxlen], b[maxlen], c[maxlen];
int memmove(int dst[], int dst_pos, int src[], int len){
int i = 0;
while (i < len){
dst[dst_pos + i] = src[i];
i = i + 1;
}
return i;
}
int fft(int arr[], int begin_pos, int n, int w){
if (n == 1) return 1;
int i = 0;
while (i < n){
if (i % 2 == 0) temp[i / 2] = arr[i + begin_pos];
else temp[n / 2 + i / 2] = arr[i + begin_pos];
i = i + 1;
}
memmove(arr, begin_pos, temp, n);
fft(arr, begin_pos, n / 2, multiply(w, w));
fft(arr, begin_pos + n / 2, n / 2, multiply(w, w));
i = 0;
int wn = 1;
while (i < n / 2){
int x = arr[begin_pos + i];
int y = arr[begin_pos + i + n / 2];
arr[begin_pos + i] = (x + multiply(wn, y)) % mod;
arr[begin_pos + i + n / 2] = (x - multiply(wn, y) + mod) % mod;
wn = multiply(wn, w);
i = i + 1;
}
return 0;
}
int main(){
int n = getarray(a);
int m = getarray(b);
starttime();
d = 1;
while (d < n + m - 1){
d = d * 2;
}
fft(a, 0, d, power(3, (mod - 1) / d));
fft(b, 0, d, power(3, (mod - 1) / d));
int i = 0;
while (i < d){
a[i] = multiply(a[i], b[i]);
i = i + 1;
}
fft(a, 0, d, power(3, mod-1 - (mod-1)/d));
i = 0;
while (i < d){
a[i] = multiply(a[i], power(d, mod-2));
i = i + 1;
}
stoptime();
putarray(n + m - 1, a);
return 0;
}

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@ -0,0 +1,112 @@
int sheet1[500][500] = {};
int sheet2[500][500] = {};
int active = 1;
int width;
int height;
int steps;
void read_map() {
width = getint();
height = getint();
// width <= 498, height <= 498
steps = getint();
getch();
int i = 1;
int j = 1;
while (j <= height) {
i = 1;
while (i <= width) {
int get = getch();
if (get == 35) {
sheet1[j][i] = 1;
} else {
sheet1[j][i] = 0;
}
i = i + 1;
}
// line feed
getch();
j = j + 1;
}
}
void put_map() {
int i = 1;
int j = 1;
while (j <= height) {
i = 1;
while (i <= width) {
if (sheet1[j][i] == 1) {
putch(35);
} else {
putch(46);
}
i = i + 1;
}
// line feed
putch(10);
j = j + 1;
}
}
void swap12() {
int i = 1;
int j = 1;
while (j <= height) {
i = 1;
while (i <= width) {
sheet1[j][i] = sheet2[j][i];
i = i + 1;
}
j = j + 1;
}
}
void step(int source[][500], int target[][500]) {
int i = 1;
int j = 1;
while (j <= height) {
i = 1;
while (i <= width) {
int alive_count = source[j - 1][i - 1] + source[j - 1][i] +
source[j - 1][i + 1] + source[j][i - 1] +
source[j][i + 1] + source[j + 1][i - 1] +
source[j + 1][i] + source[j + 1][i + 1];
if (source[j][i] == 1 && alive_count == 2 ) {
target[j][i] = 1;
} else if (alive_count == 3) {
target[j][i] = 1;
} else {
target[j][i] = 0;
}
i = i + 1;
}
j = j + 1;
}
}
int main() {
read_map();
starttime();
while (steps > 0) {
if (active == 1) {
step(sheet1, sheet2);
active = 2;
} else {
step(sheet2, sheet1);
active = 1;
}
steps = steps - 1;
}
stoptime();
if (active == 2) {
swap12();
}
put_map();
return 0;
}

@ -0,0 +1,331 @@
int func(int n) {
int sum = 0;
int i = 200;
int j = 0;
int s[100];
int m = 0;
while (m < 100){
s[m] = 0;
m=m+1;
}
while(j < n) {
if (i > 1){
s[1] = 1;
if (i > 2){
s[2] = 2;
if (i > 3){
s[3] = 3;
if (i > 4){
s[4] = 4;
if (i > 5){
s[5] = 5;
if (i > 6){
s[6] = 6;
if (i > 7){
s[7] = 7;
if (i > 8){
s[8] = 8;
if (i > 9){
s[9] = 9;
if (i > 10){
s[10] = 10;
if (i > 11){
s[11] = 11;
if (i > 12){
s[12] = 12;
if (i > 13){
s[13] = 13;
if (i > 14){
s[14] = 14;
if (i > 15){
s[15] = 15;
if (i > 16){
s[16] = 16;
if (i > 17){
s[17] = 17;
if (i > 18){
s[18] = 18;
if (i > 19){
s[19] = 19;
if (i > 20){
s[20] = 20;
if (i > 21){
s[21] = 21;
if (i > 22){
s[22] = 22;
if (i > 23){
s[23] = 23;
if (i > 24){
s[24] = 24;
if (i > 25){
s[25] = 25;
if (i > 26){
s[26] = 26;
if (i > 27){
s[27] = 27;
if (i > 28){
s[28] = 28;
if (i > 29){
s[29] = 29;
if (i > 30){
s[30] = 30;
if (i > 31){
s[31] = 31;
if (i > 32){
s[32] = 32;
if (i > 33){
s[33] = 33;
if (i > 34){
s[34] = 34;
if (i > 35){
s[35] = 35;
if (i > 36){
s[36] = 36;
if (i > 37){
s[37] = 37;
if (i > 38){
s[38] = 38;
if (i > 39){
s[39] = 39;
if (i > 40){
s[40] = 40;
if (i > 41){
s[41] = 41;
if (i > 42){
s[42] = 42;
if (i > 43){
s[43] = 43;
if (i > 44){
s[44] = 44;
if (i > 45){
s[45] = 45;
if (i > 46){
s[46] = 46;
if (i > 47){
s[47] = 47;
if (i > 48){
s[48] = 48;
if (i > 49){
s[49] = 49;
if (i > 50){
s[50] = 50;
if (i > 51){
s[51] = 51;
if (i > 52){
s[52] = 52;
if (i > 53){
s[53] = 53;
if (i > 54){
s[54] = 54;
if (i > 55){
s[55] = 55;
if (i > 56){
s[56] = 56;
if (i > 57){
s[57] = 57;
if (i > 58){
s[58] = 58;
if (i > 59){
s[59] = 59;
if (i > 60){
s[60] = 60;
if (i > 61){
s[61] = 61;
if (i > 62){
s[62] = 62;
if (i > 63){
s[63] = 63;
if (i > 64){
s[64] = 64;
if (i > 65){
s[65] = 65;
if (i > 66){
s[66] = 66;
if (i > 67){
s[67] = 67;
if (i > 68){
s[68] = 68;
if (i > 69){
s[69] = 69;
if (i > 70){
s[70] = 70;
if (i > 71){
s[71] = 71;
if (i > 72){
s[72] = 72;
if (i > 73){
s[73] = 73;
if (i > 74){
s[74] = 74;
if (i > 75){
s[75] = 75;
if (i > 76){
s[76] = 76;
if (i > 77){
s[77] = 77;
if (i > 78){
s[78] = 78;
if (i > 79){
s[79] = 79;
if (i > 80){
s[80] = 80;
if (i > 81){
s[81] = 81;
if (i > 82){
s[82] = 82;
if (i > 83){
s[83] = 83;
if (i > 84){
s[84] = 84;
if (i > 85){
s[85] = 85;
if (i > 86){
s[86] = 86;
if (i > 87){
s[87] = 87;
if (i > 88){
s[88] = 88;
if (i > 89){
s[89] = 89;
if (i > 90){
s[90] = 90;
if (i > 91){
s[91] = 91;
if (i > 92){
s[92] = 92;
if (i > 93){
s[93] = 93;
if (i > 94){
s[94] = 94;
if (i > 95){
s[95] = 95;
if (i > 96){
s[96] = 96;
if (i > 97){
s[97] = 97;
if (i > 98){
s[98] = 98;
if (i > 99){
s[99] = 99;
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
j=j+1;
int m = 0;
while (m < 100){
sum = sum + s[m];
m=m+1;
}
sum = sum % 65535;
}
return sum;
}
int main() {
starttime();
int loopcount = getint();
putint(func(loopcount));
putch(10);
stoptime();
return 0;
}

@ -0,0 +1,49 @@
int COUNT = 500000;
float loop(float x[], float y[], int length) {
int i = 0;
float accumulator = 0.0;
while (i < length) {
accumulator = accumulator + x[i] * y[i];
i = i + 1;
}
return accumulator;
}
int main() {
int i = 0, j = 0;
int len = getint();
float x[4096];
float y[4096];
float total = 0.0;
float a = 0.0;
float b = 1.0;
starttime();
while ( i < COUNT) {
if (i % 10) {
a = 0.0;
b = 1.0;
} else {
a = a + 0.1;
b = b + 0.2;
}
while ( j < len) {
x[j] = a + j;
y[j] = b + j;
j = j + 1;
}
total = total + loop(x, y, len);
i = i + 1;
}
stoptime();
if ((total - 11442437121638400.000000) <=0.000001 || (total - 11442437121638400.000000) >= -0.000001) {
putint(0);
return 0;
}
else {
putint(1);
return 1;
}
}

@ -0,0 +1,2 @@
10000000
30 2 5 4 25 8 125 16 625 32 3125 2 5 4 25 8 125 16 625 32 3125 2 5 4 25 8 125 16 625 32 3125

@ -0,0 +1,51 @@
int matrix[20000000];
int a[100000];
int transpose(int n, int matrix[], int rowsize){
int colsize = n / rowsize;
int i = 0;
int j = 0;
while (i < colsize){
j = 0;
while (j < rowsize){
if (i < j){
j = j + 1;
continue;
}
int curr = matrix[i * rowsize + j];
matrix[j * colsize + i] = matrix[i * rowsize + j];
matrix[i * rowsize + j] = curr;
j = j + 1;
}
i = i + 1;
}
return -1;
}
int main(){
int n = getint();
int len = getarray(a);
starttime();
int i = 0;
while (i < n){
matrix[i] = i;
i = i + 1;
}
i = 0;
while (i < len){
transpose(n, matrix, a[i]);
i = i + 1;
}
int ans = 0;
i = 0;
while (i < len){
ans = ans + i * i * matrix[i];
i = i + 1;
}
if (ans < 0) ans = -ans;
stoptime();
putint(ans);
putch(10);
return 0;
}

@ -0,0 +1,85 @@
int func(int i, int j) {
return ((i+j) * (i+j+1) / 2 + i + 1);
}
float Vectordot(float v[], float u[], int n) {
int i = 0;
float sum = 0;
while (i < n) {
sum =sum+ v[i] * u[i];
i=i+1;
}
return sum;
}
void mult1(float v[], float out[],int n) {
int i = 0, j = 0;
float sum = 0;
while (i < n) {
while (j < n) {
sum =sum+ v[j] / func(i,j);
j=j+1;
}
out[i] = sum;
i=i+1;
}
}
void mult2(float v[], float out[], int n) {
int i = 0, j = 0;
float sum = 0;
while (i < n) {
while (j < n) {
sum =sum+ v[j] / func(j,i);
j=j+1;
}
out[i] = sum;
i=i+1;
}
}
void mult_combin(float v[], float out[], int n, float tmp[]) {
mult1(v, tmp, n);
mult2(tmp, out, n);
}
float temp = 1;
float my_sqrt(float input) {
while (temp - input / temp > 1e-6 || temp - input / temp < -1e-6){
temp = (temp+input/temp)/2;
}
return temp;
}
int main() {
int n = 100000;
if (n <= 0) {
n = 2000;
}
starttime();
float vectorA[100000], vectorB[100000], Vectortmp[100000];
int i;
while(i < n) {
vectorA[i] = 1;
i=i+1;
}
i = 0;
while(i < 1000) {
mult_combin(vectorA, vectorB, n, Vectortmp);
mult_combin(vectorB, vectorA, n, Vectortmp);
i=i+1;
}
stoptime();
float result = my_sqrt(Vectordot(vectorA,vectorB, n) / Vectordot(vectorB,vectorB,n));
if(result - 1.000000 <= 1e-6 && result - 1.000000 >= -1e-6){
putint(1);
}else{
putint(0);
}
putch(10);
return 0;
}
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