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<main>
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<h1 id="使用迭代器来改进我们的程序"><a class="header" href="#使用迭代器来改进我们的程序">使用迭代器来改进我们的程序</a></h1>
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<blockquote>
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<p>本章节是可选内容,请大家在看完<a href="https://course.rs/advance/functional-programing/iterator.html">迭代器章节</a>后,再来阅读</p>
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</blockquote>
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<p>在之前的 <code>minigrep</code> 中,功能虽然已经 ok,但是一些细节上还值得打磨下,下面一起看看如何使用迭代器来改进 <code>Config::build</code> 和 <code>serach</code> 的实现。</p>
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<h2 id="移除-clone-的使用"><a class="header" href="#移除-clone-的使用">移除 <code>clone</code> 的使用</a></h2>
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<p>虽然之前有讲过为什么这里可以使用 <code>clone</code>,但是也许总有同学心有芥蒂,毕竟程序员嘛,都希望代码处处完美,而不是丑陋的处处妥协。</p>
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<pre><pre class="playground"><code class="language-rust edition2021">
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<span class="boring">#![allow(unused)]
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</span><span class="boring">fn main() {
|
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|
</span>impl Config {
|
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pub fn build(args: &[String]) -> Result<Config, &'static str> {
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if args.len() < 3 {
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return Err("not enough arguments");
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}
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let query = args[1].clone();
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let file_path = args[2].clone();
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let ignore_case = env::var("IGNORE_CASE").is_ok();
|
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Ok(Config {
|
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|
query,
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|
file_path,
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|
ignore_case,
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})
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}
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}
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<span class="boring">}
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</span></code></pre></pre>
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<p>之前的代码大致长这样,两行 <code>clone</code> 确实有点啰嗦,好在,在学习完迭代器后,我们知道了 <code>build</code> 函数实际上可以<strong>直接拿走迭代器的所有权</strong>,而不是去借用一个数组切 <code>&[String]</code>。</p>
|
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|
<p>这里先不给出代码,下面统一给出。</p>
|
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|
<h2 id="直接使用返回的迭代器"><a class="header" href="#直接使用返回的迭代器">直接使用返回的迭代器</a></h2>
|
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|
|
<p>在之前的实现中,我们的 <code>args</code> 是一个动态数组:</p>
|
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|
<pre><pre class="playground"><code class="language-rust edition2021">fn main() {
|
|
|
|
|
let args: Vec<String> = env::args().collect();
|
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|
|
|
|
|
|
|
let config = Config::build(&args).unwrap_or_else(|err| {
|
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|
eprintln!("Problem parsing arguments: {err}");
|
|
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|
|
process::exit(1);
|
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|
});
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|
|
|
|
// --snip--
|
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|
|
}
|
|
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|
</code></pre></pre>
|
|
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|
<p>当时还提到了 <code>collect</code> 方法的使用,相信大家学完迭代器后,对这个方法会有更加深入的认识。</p>
|
|
|
|
|
<p>现在呢,无需数组了,直接传入迭代器即可:</p>
|
|
|
|
|
<pre><pre class="playground"><code class="language-rust edition2021">fn main() {
|
|
|
|
|
let config = Config::build(env::args()).unwrap_or_else(|err| {
|
|
|
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|
eprintln!("Problem parsing arguments: {err}");
|
|
|
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|
process::exit(1);
|
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|
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|
});
|
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|
|
|
|
|
|
|
|
// --snip--
|
|
|
|
|
}
|
|
|
|
|
</code></pre></pre>
|
|
|
|
|
<p>如上所示,我们甚至省去了一行代码,原因是 <code>env::args</code> 可以直接返回一个迭代器,再作为 <code>Config::build</code> 的参数传入,下面再来改写 <code>build</code> 方法。</p>
|
|
|
|
|
<pre><pre class="playground"><code class="language-rust edition2021">
|
|
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|
|
<span class="boring">#![allow(unused)]
|
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|
|
</span><span class="boring">fn main() {
|
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|
|
|
</span>impl Config {
|
|
|
|
|
pub fn build(
|
|
|
|
|
mut args: impl Iterator<Item = String>,
|
|
|
|
|
) -> Result<Config, &'static str> {
|
|
|
|
|
// --snip--
|
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|
<span class="boring">}
|
|
|
|
|
</span></code></pre></pre>
|
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|
|
|
<p>为了可读性和更好的通用性,这里的 <code>args</code> 类型并没有使用本身的 <code>std::env::Args</code> ,而是使用了特征约束的方式来描述 <code>impl Iterator<Item = String></code>,这样意味着 <code>arg</code> 可以是任何实现了 <code>String</code> 迭代器的类型。</p>
|
|
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|
<p>还有一点值得注意,由于迭代器的所有权已经转移到 <code>build</code> 内,因此可以直接对其进行修改,这里加上了 <code>mut</code> 关键字。</p>
|
|
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|
<h2 id="移除数组索引的使用"><a class="header" href="#移除数组索引的使用">移除数组索引的使用</a></h2>
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<p>数组索引会越界,为了安全性和简洁性,使用 <code>Iterator</code> 特征自带的 <code>next</code> 方法是一个更好的选择:</p>
|
|
|
|
|
<pre><pre class="playground"><code class="language-rust edition2021">
|
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|
|
|
<span class="boring">#![allow(unused)]
|
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|
|
|
</span><span class="boring">fn main() {
|
|
|
|
|
</span>impl Config {
|
|
|
|
|
pub fn build(
|
|
|
|
|
mut args: impl Iterator<Item = String>,
|
|
|
|
|
) -> Result<Config, &'static str> {
|
|
|
|
|
// 第一个参数是程序名,由于无需使用,因此这里直接空调用一次
|
|
|
|
|
args.next();
|
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|
|
|
|
|
|
|
|
let query = match args.next() {
|
|
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|
Some(arg) => arg,
|
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|
|
None => return Err("Didn't get a query string"),
|
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|
|
|
};
|
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|
|
|
|
|
|
|
|
let file_path = match args.next() {
|
|
|
|
|
Some(arg) => arg,
|
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|
|
None => return Err("Didn't get a file path"),
|
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|
|
|
};
|
|
|
|
|
|
|
|
|
|
let ignore_case = env::var("IGNORE_CASE").is_ok();
|
|
|
|
|
|
|
|
|
|
Ok(Config {
|
|
|
|
|
query,
|
|
|
|
|
file_path,
|
|
|
|
|
ignore_case,
|
|
|
|
|
})
|
|
|
|
|
}
|
|
|
|
|
}
|
|
|
|
|
<span class="boring">}
|
|
|
|
|
</span></code></pre></pre>
|
|
|
|
|
<p>喔,上面使用了迭代器和模式匹配的代码,看上去是不是很 Rust?我想我们已经走在了正确的道路上。</p>
|
|
|
|
|
<h2 id="使用迭代器适配器让代码更简洁"><a class="header" href="#使用迭代器适配器让代码更简洁">使用迭代器适配器让代码更简洁</a></h2>
|
|
|
|
|
<p>为了帮大家更好的回忆和对比,之前的 <code>search</code> 长这样:</p>
|
|
|
|
|
<pre><pre class="playground"><code class="language-rust edition2021">
|
|
|
|
|
<span class="boring">#![allow(unused)]
|
|
|
|
|
</span><span class="boring">fn main() {
|
|
|
|
|
</span>// in lib.rs
|
|
|
|
|
pub fn search<'a>(query: &str, contents: &'a str) -> Vec<&'a str> {
|
|
|
|
|
let mut results = Vec::new();
|
|
|
|
|
|
|
|
|
|
for line in contents.lines() {
|
|
|
|
|
if line.contains(query) {
|
|
|
|
|
results.push(line);
|
|
|
|
|
}
|
|
|
|
|
}
|
|
|
|
|
|
|
|
|
|
results
|
|
|
|
|
}
|
|
|
|
|
<span class="boring">}
|
|
|
|
|
</span></code></pre></pre>
|
|
|
|
|
<p>引入了迭代器后,就连古板的 <code>search</code> 函数也可以变得更 rusty 些:</p>
|
|
|
|
|
<pre><pre class="playground"><code class="language-rust edition2021">
|
|
|
|
|
<span class="boring">#![allow(unused)]
|
|
|
|
|
</span><span class="boring">fn main() {
|
|
|
|
|
</span>pub fn search<'a>(query: &str, contents: &'a str) -> Vec<&'a str> {
|
|
|
|
|
contents
|
|
|
|
|
.lines()
|
|
|
|
|
.filter(|line| line.contains(query))
|
|
|
|
|
.collect()
|
|
|
|
|
}
|
|
|
|
|
<span class="boring">}
|
|
|
|
|
</span></code></pre></pre>
|
|
|
|
|
<p>Rock,让我们的函数编程 Style rock 起来,这种一行到底的写法有时真的让人沉迷。</p>
|
|
|
|
|
<h2 id="总结"><a class="header" href="#总结">总结</a></h2>
|
|
|
|
|
<p>至此,整个大章节全部结束,本章没有试图覆盖已学的方方面面( 也许未来会 ),而是聚焦于 Rust 的一些核心知识:所有权、生命周期、借用、模式匹配等等。</p>
|
|
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|
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<p>强烈推荐大家忘记已有的一切,自己重新实现一遍 <code>minigrep</code>,甚至可以根据自己的想法和喜好,来完善一些,也欢迎在评论中附上自己的练习项目,供其它人学习参考( 提个小建议,项目主页写清楚新增的功能、亮点等 )。</p>
|
|
|
|
|
<p>从下一章开始,我们将正式开始 Rust 进阶学习,请深呼吸一口,然后问自己:你..准备好了吗?</p>
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