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## 数据库字段说明
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# status 0:已开启;1:正在评测;2:通过评测;3:锁定
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# modify_time: 与challenges表的modify_time联合使用,2个字段一致,则标识测试集未修改,反之,被修改
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# answer_open: 查看查看答案的深度, 0: 未查看过答案, 其他数值与challenge_answer的level值相关
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# answer_deduction: 查看答案扣分的百分比;如 查看答案 扣除70%
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#
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class Game < ApplicationRecord
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default_scope { order("games.created_at desc") }
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has_many :outputs, -> { order('query_index DESC') }
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has_many :challenge_samples, :dependent => :destroy
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has_many :game_codes, :dependent => :destroy
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has_many :evaluate_records, -> { order('id DESC') }, :dependent => :destroy
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belongs_to :myshixun
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belongs_to :user
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belongs_to :challenge
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has_one :run_code_message, :dependent => :destroy
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#全部关卡数
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scope :ch_games, lambda { |challenge_id| where(challenge_id:challenge_id) }
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# 已通关的数量
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scope :finished_num, -> (challenge_id) { where(:challenge_id => challenge_id, :status => 1)}
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# 正在通关的数量
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scope :doing_num, -> (challenge_id) { where(:challenge_id => challenge_id, :status => 0)}
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#用户的全部关卡
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scope :user_games, lambda { |user_id,challenge_id| where("user_id = ? AND challenge_id = ?",user_id,challenge_id) }
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validates :identifier, uniqueness: true
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# 根据得分比例来算实际得分(试卷、实训作业)
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def real_score score
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final_score == challenge.score ? score : (final_score.to_f / challenge.score) * score
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end
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# 判断实训是否全部通关
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def had_done
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Game.where(myshixun: self.myshixun_id).where("status != 2").count > 0 ? 0 : 1
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end
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def owner
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self.user
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end
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def had_passed?
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self.status == 2
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end
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# 因为outputs是按qurey_index倒序,所有first取的qurey_index的最大值
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# 之所以加1是因为,存的时候要递增,如果仅取的话,则注意:必须减一
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def query_index
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# Output.unscope(:order).maximum("query_index").where(game_id: self.id)
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self.outputs.unscope(:order).maximum("query_index")
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end
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# 用户在game关卡中获得的金币和经验值
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# st: 0 实战类型;1 选择题类型
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def user_get_gold_and_experience shixun_status, challenge
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if challenge.st == 0 # 实战类型
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if self.status == 2 # 通关了则取实际得分,没通关则取总分
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gold = (shixun_status <= 1) ? 0 : self.final_score.to_i
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# 只要过关了,查看了答案经验值就是0;通关前查看了答案金final_score为负数
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experience = (shixun_status <= 1 || self.final_score.to_i < 0) ? 0 : challenge.score.to_i
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else
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gold = challenge.score.to_i
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experience = gold
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end
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else
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if self.status == 2
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gold = (shixun_status <= 1) ? 0 : self.final_score.to_i
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experience = (shixun_status <= 1 || self.final_score.to_i < 0) ? 0 : challenge.score.to_i
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else
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# 选择题只有在全对的时候才会获取final score总分,错任何一个题final_score就为0
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gold = challenge.choose_score
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experience = challenge.choose_score
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end
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end
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[gold, experience]
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end
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# 上一关
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def prev_of_current_game shixun_id, myshixun_id, challenge_position
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Game.find_by_sql("select identifier from games where myshixun_id=#{myshixun_id}
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and challenge_id=(select id from challenges where shixun_id=#{shixun_id} and
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position=#{challenge_position - 1})").first.try(:identifier)
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end
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# 下一关
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def next_of_current_game shixun_id, myshixun_id, challenge_position
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Game.find_by_sql("select * from games where myshixun_id=#{myshixun_id}
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and challenge_id=(select id from challenges where shixun_id=#{shixun_id} and
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position=#{challenge_position + 1})").first.try(:identifier)
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end
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# 针对api形式取下一关identifier
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def next_game shixun_id, myshixun_id, challenge_position
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Game.find_by_sql("select * from games where myshixun_id=#{myshixun_id}
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and challenge_id=(select id from challenges where shixun_id=#{shixun_id} and
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position=#{challenge_position + 1})").first
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end
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# 因为outputs是按qurey_index倒序,所有first取的qurey_index的最大值
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# 之所以加1是以为,存的时候要递增,如果仅取的话,则注意:必须减一
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def next_query_index
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if self.outputs.try(:first).present?
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self.outputs.first.try(:query_index).to_i + 1
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else
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1
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end
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end
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def choose_correct_num query_index
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self.outputs.where(query_index: query_index, result: 1).count
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end
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# 评测次数
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def evaluate_count
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self.outputs.pluck(:query_index).first
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end
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# 用户关卡得分
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def get_user_final_score
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end
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# 按评测次数的查询
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def distinct_query_index
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self.outputs.group("outputs.query_index").reorder("query_index asc")
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end
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def lastest_code
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self.game_codes.first.try(:new_code)
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# game_code = GameCode.where(:game_id => self.id).first
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# game_code.try(:new_code)
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end
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end
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