#! /bin/bash
# this function takes a string in version format (s.a 2.6.16) and makes it an integer (00020006001600000000)
function digit_version { echo $1 | awk -F. '{ printf("%04d%04d%04d\n", $1, $2, $3); }'; }

if [ -f $1 ]; then \
if [[ $(digit_version `$1 --version | egrep -o "[1-9]{1}\.[1-9]{1}(\.[0-9]*)?" | head -1`) < $(digit_version $2) ]]; then echo 1; else echo 0; fi \
else echo 0; fi