CodePattern/一盘大棋/A03.py

import re, collections
from cppy.cp_util import stopwordfilepath,testfilepath

stopwords = set(open( stopwordfilepath,encoding = 'utf8' ).read().split(','))
words = re.findall('[a-z]{2,}', open( testfilepath,encoding = 'utf8').read().lower())
counts = collections.Counter(w for w in words if w not in stopwords)
for (w, c) in counts.most_common(10) :  print(w, '-', c)

'''
熟练的软件工程师，会如此简单完成任务
后面的例子，我们必须变的啰嗦一些，不能用这种太 hacker 的写法
'''