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Sudo/main/sudo.py

117 lines
3.5 KiB

8 months ago
import random
import numpy as np
# 获取格子所在的行的全部格子
def get_row(sudo, row):
return sudo[row, :]
# 获取格子所在的列的全部格子
def get_col(sudo, col):
return sudo[:, col]
# 获取格子所在的九宫格的全部格子
def get_block(sudo, row, col):
row_start = row // 3 * 3
col_start = col // 3 * 3
return sudo[row_start: row_start + 3, col_start: col_start + 3]
# 打印数独
def print_sudo(sudo):
for row_index, row in enumerate(sudo):
if row_index % 3 == 0 and row_index != 0:
print('-' * (9 + 8 + 4))
row = list(map(str, row.tolist()))
row.insert(6, '|')
row.insert(3, '|')
row_str = ' '.join(row)
print(row_str.replace('0', ' '))
def create_base_sudo():
# 9*9的二维矩阵每个格子默认值为0
sudo = np.zeros((9, 9), dtype=int)
# 随机生成起始的基数(1 ~ 9)
num = random.randrange(9) + 1
# 遍历从左到右,从上到下逐个遍历
for row_index in range(9):
for col_index in range(9):
# 获取该格子对应的行、列、九宫格
sudo_row = get_row(sudo, row_index)
sudo_col = get_col(sudo, col_index)
sudo_block = get_block(sudo, row_index, col_index)
# 如果该数字已经存在于对应的行、列、九宫格
# 则继续判断下一个候选数字,直到没有重复
while num in sudo_row or num in sudo_col or num in sudo_block:
num = num % 9 + 1
# 赋值
sudo[row_index, col_index] = num
num = num % 9 + 1
return sudo
def random_sudo(sudo, times):
for _ in range(times):
# 随机交换两行
rand_row_base = random.randrange(3) * 3 # 从036 随机取一个
rand_rows = random.sample(range(3), 2) # 从 012中随机取两个数
row_1 = rand_row_base + rand_rows[0]
row_2 = rand_row_base + rand_rows[1]
sudo[[row_1, row_2], :] = sudo[[row_2, row_1], :]
# 随机交换两列
rand_col_base = random.randrange(3) * 3
rand_cols = random.sample(range(3), 2)
col_1 = rand_col_base + rand_cols[0]
col_2 = rand_col_base + rand_cols[1]
sudo[:, [col_1, col_2]] = sudo[:, [col_2, col_1]]
def get_sudo_subject(sudo, del_nums):
subject = sudo.copy()
# 随机擦除从0到80随机取要删除的个数
clears = random.sample(range(81), del_nums)
for clear_index in clears:
# 把0到80的坐标转化成行和列索引
# 这样就不会重复删除同一个格子的数字
row_index = clear_index // 9
col_index = clear_index % 9
subject[row_index, col_index] = 0
return subject
if __name__ == '__main__':
max_clear_count = 64 # 最多清除个数
min_clear_count = 14 # 最少清除个数
# 设置难度等级1~55个等级入门、初级、熟练、精通、大神
level = 3
# 每个等级的个数
each_level_count = (max_clear_count - min_clear_count) / 5
# 该等级最小数
level_start = min_clear_count + (level - 1) * each_level_count
# 该等级范围内的随机数
del_nums = random.randrange(level_start, level_start + each_level_count)
# 生成基本盘
sudo = create_base_sudo()
# 生成终盘
random_sudo(sudo, 50)
# 获取数独题目
subject = get_sudo_subject(sudo, del_nums)
print('题目:')
print('=' * 26)
print_sudo(subject)
print('\n答案:')
print('=' * 26)
print_sudo(sudo)