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#include<stdio.h>
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#include<math.h>
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#include<stdlib.h>
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#include<time.h>
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// 每月天数
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int month_day(int year,int month)
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{
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switch(month)
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{
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case 1:
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case 3:
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case 5:
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case 7:
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case 8:
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case 10:
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case 12:
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return 31;break;
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case 4:
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case 6:
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case 9:
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case 11:
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return 30;break;
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case 2:
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if((year%4==0)&&(year%100!=0)||(year%400==0))
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{
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return 29;
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break;
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}
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else
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{
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return 28;
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break;
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}
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}
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}
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// 年历
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void year_calendar(int year)
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{
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int month,days,weekday,sum_day;
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int i,j;
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year;
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printf("请输入要查询的年份：");
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scanf("%d",&year);
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for(i=1;i<year;i++)
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{
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if((year%4==0)&&(year%100!=0)||(year%400==0))
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sum_day+=366;
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else
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sum_day+=365;
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}
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for(month=1;month<=12;month++)
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{
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printf("\n--------%d/%d--------\n",year,month);
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printf("SUN\tMON\tTUE\tWED\tTHU\tFRI\tSAT\t\n");
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i=1;
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j=1;
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weekday=sum_day%7;
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while(i<=weekday) //开始位置前都是空格
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{
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printf("\t");
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i++;
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}
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while(j<=month_day(year,month))
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{
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weekday=sum_day%7;
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if (weekday==6)
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printf("%d\n",j);
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else
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printf("%d\t",j);
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if(j==month_day(year,month))
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printf("\n");
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j++;
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sum_day++;
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}
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}
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}
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// 月历
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void month_calendar(int year,int month)
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{
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int sum_day=0,weekday,i,j,k;
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printf("请输入要查询的年/月：");
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scanf("%d/%d",&year,&month);
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for(i=1;i<year;i++)
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{
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if((year%4==0)&&(year%100!=0)||(year%400==0))
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sum_day+=366;
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else
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sum_day+=365;
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}
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for(k=1;k<month;k++)
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{
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sum_day+=month_day(year,month);
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}
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printf("\n\t--------%d/%d--------\n",year,month);
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printf("\tSUN\tMON\tTUE\tWED\tTHU\tFRI\tSAT\t\n");
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i=1;
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j=1;
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weekday=sum_day%7;
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while(i<=weekday) //开始位置前都是空格
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{
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printf("\t");
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i++;
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}
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while(j<=month_day(year,month))
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{
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weekday=sum_day%7;
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if (weekday==6)
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printf("%d\n",j);
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else
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printf("%d\t",j);
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if(j==month_day(year,month))
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printf("\n");
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j++;
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sum_day++;
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}
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}
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// 距今多少天
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void Time(int year,int month,int day)
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{
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time_t t;//将t声明为时间变量
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struct tm *p;//struct tm是一个结构体，声明一个结构体指针
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time(&t);
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p=localtime(&t);//获得当前时间
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int now_year,now_month,now_day;
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now_year=1900+p->tm_year;
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now_month=1+p->tm_mon;
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now_day=p->tm_mday;
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printf("当前日期是：%d/%d/%d\n",now_year,now_month,now_day);
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//输入日期的总天数
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int i,k,sum_day;
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printf("请输入要查询的年/月/日：");
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scanf("%d/%d/%d",&year,&month,&day);
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for(i=1;i<year;i++)
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{
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if((year%4==0)&&(year%100!=0)||(year%400==0))
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sum_day+=366;
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else
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sum_day+=365;
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}
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for(k=1;k<month;k++)
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{
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sum_day+=month_day(year,month);
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}
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sum_day+=day;
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//当前总日期
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int j,sum_nowday;
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for(j=1;j<now_year;j++)
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{
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if((now_year%4==0)&&(now_year%100!=0)||(now_year%400==0))
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sum_nowday+=366;
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else
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sum_nowday+=365;
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}
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for(k=1;k<now_month;k++)
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{
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sum_nowday+=month_day(now_year,now_month);
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}
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sum_nowday+=now_day;
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//相减得差值
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if(sum_day>sum_nowday)
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printf("\n输入日期与当前日期相差%d天",sum_day-sum_nowday);
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else
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printf("\n输入日期与当前日期相差%d天",sum_nowday-sum_day);
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}
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//日期查询
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void rq(int year,int month,int day)
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{
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printf("请输入要查询的年/月/日：");
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int sum_day,i,k,weekday;
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scanf("%d/%d/%d",&year,&month,&day);
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for(i=1;i<year;i++)
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{
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if((year%4==0)&&(year%100!=0)||(year%400==0))
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sum_day+=366;
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else
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sum_day+=365;
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}
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for(k=1;k<month;k++)
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{
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sum_day+=month_day(year,month);
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}
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sum_day+=day;
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weekday=sum_day%7;
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printf("\n");
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switch(weekday)
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{
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case 0:
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{
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printf("星期日");
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break;
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}
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case 1:
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{
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printf("星期一");
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break;
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}
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case 2:
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{
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printf("星期二");
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break;
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}
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case 3:
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{
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printf("星期三");
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break;
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}
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case 4:
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{
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printf("星期四");
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break;
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}
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case 5:
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{
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printf("星期五");
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break;
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}
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case 6:
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{
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printf("星期六");
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break;
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}
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}
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printf("\n\n");
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if(month==1)
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{
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if(day==1)
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printf("元旦");
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}
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else if(month==2)
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{
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if(day==14)
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printf("情人节");
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}
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else if(month==3)
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{
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switch(day)
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{
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case 8:printf("妇女节");break;
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case 12:printf("植树节");break;
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}
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}
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else if(month==4)
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{
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if(day==1)
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printf("愚人节");
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}
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else if(month==5)
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{
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switch(day)
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{
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case 1:printf("劳动节");break;
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case 4:printf("青年节");break;
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}
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}
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else if(month==6)
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{
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if(day==1)
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printf("儿童节");
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}
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else if(month==7)
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{
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if(day==1)
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printf("建党节");
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}
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else if(month==8)
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{
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if(day==1)
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printf("建军节");
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}
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else if(month==9)
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{
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if(day==10)
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printf("教师节");
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}
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else if(month==10)
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{
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if(day==1)
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printf("国庆节");
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}
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else if(month==11)
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{
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;
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}
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else
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{
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if(day==25)
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printf("圣诞节");
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}
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}
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int main(void)
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{
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printf("\n-------------------选择服务-------------------\n\n");
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printf(" 1.年历显示\n");
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printf(" 2.月历显示\n");
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printf(" 3.距今多少天\n");
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printf(" 4.日期查询\n");
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printf(" 5.退出\n");
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printf("\n-------------------选择服务-------------------\n") ;
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int n,year,month,day;
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printf("请选择服务：");
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scanf("%d",&n);
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switch(n)
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{
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case 1:
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{
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year_calendar(year);
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break;
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}
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case 2:
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{
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month_calendar(year,month);
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break;
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}
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case 3:
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{
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Time(year,month,day);
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break;
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}
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case 4:
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{
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rq(year,month,day);
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break;
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}
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case 5:
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{
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return 0;
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}
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}
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}
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