Add step5

step5

@@ -0,0 +1,56 @@
+#include<stdio.h>
+#include<string.h>
+#define size 3
+int main()
+{
+
+	//我们假设此处已有学生的信息
+	//此处排序函数，在4中已有，函数名sequence（）
+	struct Student
+	{
+		int class;//[size];
+		int number, score;
+		int ans;
+		int score1, score2, all_score;//三门成绩分别为score，score1，score2，all_score为了求和
+	}Student[size];
+	Student[0].class = 11;
+	Student[1].class = 11;
+	Student[2].class = 12;
+	Student[0].number = 10001;
+	Student[1].number = 10002;
+	Student[2].number = 10004;
+	Student[0].score = 90; Student[0].score1 = 90; Student[0].score2 = 90;
+	Student[1].score = 83; Student[1].score1 = 84; Student[1].score2 = 85;
+	Student[2].score = 83; Student[2].score1 = 70; Student[2].score2 = 90;
+	int num=10001;
+	char choic;
+	//scanf_s("%c", &choice);
+	printf("请输入你想删除的学生的编号");
+	; scanf_s("%d", &num);
+	printf("\n");
+	printf("Are you sure(yes/no)\n");
+	getchar();
+	scanf_s("%c", &choic);
+	if(choic=='y')
+	{
+		for (int count1 = 0; count1 < size; count1++)
+		{
+			if (num == Student[count1].number)
+				continue;
+			else
+			{
+				printf("%d %d %d %d %d ", Student[count1].class, Student[count1].number, Student[count1].score, Student[count1].score1, Student[count1].score2);
+			}
+			printf("\n");
+		}
+	}
+	else
+	{
+		for (int count1 = 0; count1 < size; count1++)
+		{
+			printf("%d %d %d %d %d ", Student[count1].class, Student[count1].number, Student[count1].score, Student[count1].score1, Student[count1].score2);
+			printf("\n");
+		}
+	}
+	return 0;
+}