yzf/未命名1.cpp

#include <stdio.h>
int n = 0;
int rest[7][7];
void swap(int *a, int *b)
{   
int m;   
m = *a;   
*a = *b;   
*b = m;
}
void perm(int list[], int k, int m)
{
int i;
int j;
if(k > m)
{
for (i=0; i<7; i++)
{
for (j=0; j<7; j++)
{
if (rest[i][j] == -1)
return;
if (rest[i][j] != list[i])
continue;
if (rest[i][j] == list[i])
break;
}
}
n++;
printf("Solution: %d\n", n);
printf("赵  钱  孙  李  周  吴  陈\n");
for(i = 0; i <= m; i++)
{
switch (list[i])
{
case 1: printf("星期一 ");
break;
case 2: printf("星期二 ");
break;
case 3: printf("星期三 ");
break;
case 4: printf("星期四 ");
break;
case 5: printf("星期五 ");
break;
case 6: printf("星期六 ");
break;
case 7: printf("星期日 ");
break;
default:
break;
}
}
printf("\n\n\n");
}
else
{
for(i = k; i <= m; i++)
{
swap(&list[k], &list[i]);
perm(list, k + 1, m);
swap(&list[k], &list[i]);
}
}
}
int main()
{
int list[] = {1, 2, 3, 4, 5, 6, 7};
int i, j;
char ss[7][20]={"赵","钱","孙","李","周","吴","陈"};
printf("===========================欢迎使用排班系统===================================\n");
printf("请输入下列人选选择休息的可能时间,每输完一个人的休息时间，输入-1后按回车\n");
for(i = 0; i < 7; i++)
{
 printf("%s：",ss[i]);
for(j = 0; j < 7; j++)
{
scanf("%d", &rest[i][j]);
if(rest[i][j] == -1)
break;
}
}
printf("\n\n\n");
perm(list, 0, 6);
printf("可能的方案有:%d种", n);

getchar();
return 0;
}