From 5b3b6a12a108e93a5b6feff9e16a274fbf819fa6 Mon Sep 17 00:00:00 2001 From: xuzigui <3542624849@qq.com> Date: Sun, 7 May 2023 12:24:30 +0800 Subject: [PATCH] =?UTF-8?q?XZG=5F=E4=BC=AA=E4=BB=A3=E7=A0=81?= MIME-Version: 1.0 Content-Type: text/plain; charset=UTF-8 Content-Transfer-Encoding: 8bit --- README.md | 171 +++++++++++++++++++++++------------------------------- 1 file changed, 71 insertions(+), 100 deletions(-) diff --git a/README.md b/README.md index bb1afe6..a7be773 100644 --- a/README.md +++ b/README.md @@ -657,7 +657,7 @@ function ReadScore(STU stu[],int n,int m) do int i,j; printf "Input student's ID ,name and score:\n" for from i=0 to n-1 do //输入n个同学 - + input stu[i].num,stu[i].name for form j=0 to m-1 do //输入m门成绩 input stu[i].score[j] @@ -669,191 +669,162 @@ end //函数功能:计算每个学生各门课程的总分和平均分 ``` -void AverSumofEveryStudent(STU stu[],int n,int m) -{ +function AverSumofEveryStudent(STU stu[],int n,int m) do int i,j; - for(i=0;i0 ? stu[i].sum /m : -1; - printf("student %d: sum = %.0f,aver = %.0f\n",i+1,stu[i].sum,stu[i].aver); - } -} + printf "student %d: sum = %.0f,aver = %.0f\n" + end +end ``` //函数功能:计算每门课程的总分和平均分 ``` -void AverSumofEveryCourse(STU stu[],int n,int m) -{ +function AverSumofEveryCourse(STU stu[],int n,int m) do int i,j; float sum[COURSE_NUM],aver[COURSE_NUM]; - for(j=0;j b; // 这样比较决定了按降序排序,如果 a>b,则交换 -} +end ``` //交换两个单精度浮点型数据 ``` -void SwapFloat(float *x,float *y) -{ +function SwapFloat(float *x,float *y) do float temp; temp = *x; *x = *y; *y = temp; -} +end ``` //交换两个长整型数据 ``` -void SwapLong(long *x,long *y) -{ +function SwapLong(long *x,long *y) do long temp; temp = *x; *x = *y; *y = temp; -} +end ``` //交换两个字符串 ``` -void SwapChar(char x[],char y[]) -{ +function SwapChar(char x[],char y[]) do char temp[MAX_LEN]; strcpy(temp, x); strcpy(x, y); strcpy(y, temp); -} +end ``` //函数功能:按选择法将数组 num 的元素从低到高排序 ``` -void AsSortbyNum(STU stu[],int n,int m) -{ +function AsSortbyNum(STU stu[],int n,int m) do int i, j, k, t; - for (i=0; i