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#include <stdio.h>
#include <ctime>
#define SIZE 1024
void sparse_matmul_coo(float* A_values, int* A_rowIndex, int* A_colIndex, int A_nonZeroCount,
float* B_values, int* B_rowIndex, int* B_colIndex, int B_nonZeroCount,
float* C_values, int* C_rowIndex, int* C_colIndex, int *C_nonZeroCount) {
int currentIndex = 0;
// 遍历 A 的非零元素
for (int i = 0; i < A_nonZeroCount; i++) {
int rowA = A_rowIndex[i];
int colA = A_colIndex[i];
float valueA = A_values[i];
// 遍历 B 的非零元素
for (int j = 0; j < B_nonZeroCount; j++) {
int rowB = B_rowIndex[j];
int colB = B_colIndex[j];
float valueB = B_values[j];
// 如果 A 的列和 B 的行匹配,则计算乘积并存储结果
if (colA == rowB) {
float product = valueA * valueB;
// 检查是否已有此 (rowA, colB) 项
int found = 0;
for (int k = 0; k < currentIndex; k++) {
if (C_rowIndex[k] == rowA && C_colIndex[k] == colB) {
C_values[k] += product;
found = 1;
break;
}
}
// 如果没有此项,添加新的非零元素
if (!found) {
C_values[currentIndex] = product;
C_rowIndex[currentIndex] = rowA;
C_colIndex[currentIndex] = colB;
currentIndex++;
}
}
}
}
// 更新非零元素数量
*C_nonZeroCount = currentIndex;
}
int main(){
int i;
//矩阵 A 的 COO 格式
float A_values[]={1,2,3,4,5};
int A_rowIndex[]={0,0,1,2,2};
int A_colIndex[]={0,2,1,0,2};
int A_nonZeroCount=5;
//矩阵 B 的 COO 格式
float B_values[]={6,8,7,9};
int B_rowIndex[]={0,2,1,2};
int B_colIndex[]={0,0,1,2};
int B_nonZeroCount=4;
//矩阵 C 的 COO 格式
float C_values[SIZE];
int C_rowIndex[SIZE];
int C_colIndex[SIZE];
int C_nonZeroCount=0;
//计时并输出
clock_t start=clock();
sparse_matmul_coo(A_values, A_rowIndex, A_colIndex, A_nonZeroCount,
B_values, B_rowIndex, B_colIndex, B_nonZeroCount,
C_values, C_rowIndex, C_colIndex, &C_nonZeroCount);
clock_t end=clock();
printf("初始稀疏矩阵乘法时间:%f秒\n",(double)(end-start)/CLOCKS_PER_SEC);
return 0;
}