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@ -0,0 +1,636 @@
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/*课程设计思路：
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参赛选手信息输入：
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姓名 性别 年龄 学校 项目（项目中的名次，及项目中获得的分数） 总分数
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学校信息输入：
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学校名称 学校编号 学校参加总数 学校总分数
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项目信息输入：
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选择名次方案：a种还是b种
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各名次获得者姓名：
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先输项目信息后输学校信息最后输选手信息
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选手最大人数：max=50；每人允许参加的项目最大数为：max=5；
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学校最大数目：max=10；
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项目最多数：max=15；
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建立模块之前应做：
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首先问今年共有多少学生参加比赛？及每人最多参加几个项目？
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问共有多少学校参加比赛？
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问共有多少项目？
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菜单：
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输入选手信息：
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输入学校信息：
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输入项目信息：
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寻找并输出选手信息：
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寻找并输出项目信息：
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寻找并输出学校信息：
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学校排行输出：
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参赛选手排行输出：*/
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#include<stdio.h>
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#include<stdlib.h>
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#include<string.h>
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struct xmform1{
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char name[20];
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char mc1[10];
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char mc2[10];
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char mc3[10];
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char mc4[10];
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char mc5[10];
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};
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struct xmform2{
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char name[20];
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char mc1[10];
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char mc2[10];
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char mc3[10];
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};
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struct schoolform{
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char name[20];
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char id[10];
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int number;
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int scoer;
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};
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struct studentform{
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char name[20];
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char xb[10];
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char number[10];
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int age;
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char name1[20]; //name1是选手所处学校名
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struct {
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char name[20];
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char mc[50]="无名次";
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int scoer=0;
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} xm;
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int allscoer;
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};
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int ggy(struct studentform student[]){
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printf("请输入参加比赛的选手个数\n");
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int n;
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scanf("%d",&n);
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getchar();
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int i;
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for(i=0;i<n;i++){
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printf("请输入第%d个选手的姓名：\n",i+1);
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gets(student[i].name);
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printf("输入该选手的性别:\n");
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gets(student[i].xb);
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printf("请输入该选手的编号:\n");
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gets(student[i].number);
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printf("请输入该选手的年龄：\n");
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scanf("%d",&student[i].age);
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getchar();
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printf("请输入该选手的学校名称：\n");
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gets(student[i].name1);
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printf("请输入该学生所参加的项目名称：\n");
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gets(student[i].xm.name);
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printf("当前一记录%d个学生的数据\n",i+1);
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}
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printf("输入结束\n");
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printf("********************\n");
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return n;
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}
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int ggy1(struct schoolform school[]){
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printf("请输入参加比赛的学校个数\n");
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int n;
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scanf("%d",&n);
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getchar();
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int i;
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for(i=0;i<n;i++){
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printf("请输入第%d个学校的名称：\n",i+1);
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gets(school[i].name);
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printf("请输入该学校编号：\n");
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gets(school[i].id);
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printf("请输入该学校参赛人数：\n");
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scanf("%d",&school[i].number);
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getchar();
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printf("当前一共记录了%d学校的数据\n",i+1);
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}
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printf("输入结束\n");
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printf("********************\n");
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return n;
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}
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int ggy2(struct xmform1 xm1[],struct studentform student[],struct schoolform school[],int schoolgs,int studentrs){
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printf("请输入这一类项目的个数：\n");
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int n;
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scanf("%d",&n);
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getchar();
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int i,i1,i2;
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int a1,a2;
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for(i=0;i<n;i++){
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printf("请输入该类第%d个项目名称：\n",i+1);
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gets(xm1[i].name);
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printf("输入该个项目获奖情况：第一名 第二名 第三名 第四名 第五名（依次按顺序输入姓名,注：输一个名字按一次回城）");
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gets(xm1[i].mc1);
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for(i1=0;i1<studentrs;i1++){
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a1=strcmp(xm1[i].mc1,student[i1].name);
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if(a1==0){
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strcpy(student[i1].xm.mc,"第一名");
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student[i1].xm.scoer+=7;
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for(i2=0;i2<schoolgs;i2++){
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a2=strcmp(school[i2].name,student[i1].name1);
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if(a2==0){
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school[i2].scoer+=7;
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break;
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}
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}
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break;
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}
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}
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gets(xm1[i].mc2);
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for(i1=0;i1<studentrs;i1++){
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a1=strcmp(xm1[i].mc2,student[i1].name);
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if(a1==0){
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strcpy(student[i1].xm.mc,"第二名");
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student[i1].xm.scoer+=5;
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for(i2=0;i2<schoolgs;i2++){
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a2=strcmp(school[i2].name,student[i1].name1);
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if(a2==0){
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school[i2].scoer+=5;
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break;
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}
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}
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break;
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}
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}
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gets(xm1[i].mc3);
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for(i1=0;i1<studentrs;i1++){
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a1=strcmp(xm1[i].mc3,student[i1].name);
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if(a1==0){
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strcpy(student[i1].xm.mc,"第三名");
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student[i1].xm.scoer+=3;
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for(i2=0;i2<schoolgs;i2++){
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a2=strcmp(school[i2].name,student[i1].name1);
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if(a2==0){
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school[i2].scoer+=3;
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break;
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}
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}
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break;
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}
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}
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gets(xm1[i].mc4);
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for(i1=0;i1<studentrs;i1++){
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a1=strcmp(xm1[i].mc4,student[i1].name);
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if(a1==0){
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strcpy(student[i1].xm.mc,"第四名");
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student[i1].xm.scoer+=2;
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for(i2=0;i2<schoolgs;i2++){
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a2=strcmp(school[i2].name,student[i1].name1);
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if(a2==0){
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school[i2].scoer+=2;
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break;
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}
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}
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break;
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}
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}
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gets(xm1[i].mc5);
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for(i1=0;i1<studentrs;i1++){
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a1=strcmp(xm1[i].mc5,student[i1].name);
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if(a1==0){
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strcpy(student[i1].xm.mc,"第五名");
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student[i1].xm.scoer+=1;
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for(i2=0;i2<schoolgs;i2++){
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int a2;
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a2=strcmp(school[i2].name,student[i1].name1);
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if(a2==0){
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school[i2].scoer+=1;
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break;
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}
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}
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break;
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}
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}
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printf("已输入%d个项目的情况\n",i+1);
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}
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printf("输入结束\n");
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printf("********************\n");
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return n;
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}
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int ggy3(struct xmform2 xm2[],struct studentform student[],struct schoolform school[],int schoolgs,int studentrs){
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printf("请输入这一类项目的个数：\n");
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int n;
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scanf("%d",&n);
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getchar();
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int i,i1,i2;
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int a1,a2;
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for(i=0;i<n;i++){
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printf("请输入该类第%d个项目名称：\n",i+1);
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gets(xm2[i].name);
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printf("输入该个项目获奖情况：第一名 第二名 第三名 （依次按顺序输入姓名,注：输一个名字按一次回车）");
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gets(xm2[i].mc1);
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for(i1=0;i1<studentrs;i1++){
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a1=strcmp(xm2[i].mc1,student[i1].name);
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if(a1==0){
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strcpy(student[i1].xm.mc,"第一名");
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student[i1].xm.scoer+=5;
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for(i2=0;i2<schoolgs;i2++){
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a2=strcmp(school[i2].name,student[i1].name1);
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if(a2==0){
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school[i2].scoer+=5;
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break;
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}
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}
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break;
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}
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}
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gets(xm2[i].mc2);
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for(i1=0;i1<studentrs;i1++){
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a1=strcmp(xm2[i].mc2,student[i1].name);
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if(a1==0){
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strcpy(student[i1].xm.mc,"第二名");
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student[i1].xm.scoer+=3;
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for(i2=0;i2<schoolgs;i2++){
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a2=strcmp(school[i2].name,student[i1].name1);
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if(a2==0){
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school[i2].scoer+=3;
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break;
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}
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}
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break;
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}
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}
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gets(xm2[i].mc3);
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for(i1=0;i1<studentrs;i1++){
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a1=strcmp(xm2[i].mc3,student[i1].name);
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if(a1==0){
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strcpy(student[i1].xm.mc,"第三名");
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student[i1].xm.scoer+=2;
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for(i2=0;i2<schoolgs;i2++){
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a2=strcmp(school[i2].name,student[i1].name1);
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if(a2==0){
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school[i2].scoer+=2;
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break;
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}
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}
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break;
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}
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}
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printf("已输入%d个项目的情况\n",i+1);
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}
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printf("输入结束\n");
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printf("********************\n");
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return n;
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}
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void xscz(struct studentform student[],int studentrs){ //定义一个选手查找并输出函数 （按姓名查找）
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printf("请输入你要查找的选手名字\n");
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char name[20];
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gets(name);
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int i,a,a1=0;
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for(i=0;i<studentrs;i++){
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a=strcmp(student[i].name,name);
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if(a==0){
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printf("将依次输出该选手信息：\n");
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printf("姓名：%s 性别：%s 年龄：%d 编号：%s \n",student[i].name,student[i].xb,student[i].age,student[i].number);
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printf("所属学校:%s 参加项目名称：%s 名次：%s 总分数：%d ",student[i].name1,student[i].xm.name,student[i].xm.mc,student[i].xm.scoer);
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a1=1; //防止有些选手信息未记录而找不到
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|
break;
|
|
|
|
|
}
|
|
|
|
|
}
|
|
|
|
|
if(a1==1){
|
|
|
|
|
;
|
|
|
|
|
}else{
|
|
|
|
|
printf("没有这个选手的信息\n");
|
|
|
|
|
}
|
|
|
|
|
printf("********************\n");
|
|
|
|
|
}
|
|
|
|
|
void xscz1(struct studentform student[],int studentrs){ //定义一个选手查找并输出函数 （按编号查找）
|
|
|
|
|
printf("请输入你要查找的选手编号\n");
|
|
|
|
|
char number[20];
|
|
|
|
|
gets(number);
|
|
|
|
|
int i,a,a1=0;
|
|
|
|
|
for(i=0;i<studentrs;i++){
|
|
|
|
|
a=strcmp(student[i].number,number);
|
|
|
|
|
if(a==0){
|
|
|
|
|
printf("将依次输出该选手信息：\n");
|
|
|
|
|
printf("姓名：%s 性别：%s 年龄：%d 编号：%s \n",student[i].name,student[i].xb,student[i].age,student[i].number);
|
|
|
|
|
printf("所属学校:%s 参加项目名称：%s 名次：%s 总分数：%d ",student[i].name1,student[i].xm.name,student[i].xm.mc,student[i].xm.scoer);
|
|
|
|
|
a1=1; //防止有些选手信息未记录而找不到
|
|
|
|
|
break;
|
|
|
|
|
}
|
|
|
|
|
}
|
|
|
|
|
if(a1==1){
|
|
|
|
|
;
|
|
|
|
|
}else{
|
|
|
|
|
printf("没有这个选手的信息\n");
|
|
|
|
|
}
|
|
|
|
|
printf("********************\n");
|
|
|
|
|
}
|
|
|
|
|
void xmcz1(struct xmform1 xm1[],int xmgs1){
|
|
|
|
|
printf("请输入你要查找的项目名称\n");
|
|
|
|
|
char name[20];
|
|
|
|
|
gets(name);
|
|
|
|
|
int i,a,a1=0;
|
|
|
|
|
for(i=0;i<xmgs1;i++){
|
|
|
|
|
a=strcmp(xm1[i].name,name);
|
|
|
|
|
if(a==0){
|
|
|
|
|
printf("将依次输出该项目信息：\n");
|
|
|
|
|
printf("项目名称是：%s\n",xm1[i].name);
|
|
|
|
|
printf("第一名：%s 第二名：%s 第三名：%s 第四名：%s 第五名：%s ",xm1[i].mc1,xm1[i].mc2,xm1[i].mc3,xm1[i].mc4,xm1[i].mc5);
|
|
|
|
|
a1=1; //防止有些选手信息未记录而找不到
|
|
|
|
|
break;
|
|
|
|
|
}
|
|
|
|
|
}
|
|
|
|
|
if(a1==1){
|
|
|
|
|
;
|
|
|
|
|
}else{
|
|
|
|
|
printf("没有这个项目的信息\n");
|
|
|
|
|
}
|
|
|
|
|
printf("********************\n");
|
|
|
|
|
}
|
|
|
|
|
void xmcz2(struct xmform2 xm2[],int xmgs2){
|
|
|
|
|
printf("请输入你要查找的项目名称\n");
|
|
|
|
|
char name[20];
|
|
|
|
|
gets(name);
|
|
|
|
|
int i,a,a1=0;
|
|
|
|
|
for(i=0;i<xmgs2;i++){
|
|
|
|
|
a=strcmp(xm2[i].name,name);
|
|
|
|
|
if(a==0){
|
|
|
|
|
printf("将依次输出该项目信息：\n");
|
|
|
|
|
printf("项目名称是：%s\n",xm2[i].name);
|
|
|
|
|
printf("第一名：%s 第二名：%s 第三名：%s \n",xm2[i].mc1,xm2[i].mc2,xm2[i].mc3);
|
|
|
|
|
a1=1; //防止有些选手信息未记录而找不到
|
|
|
|
|
break;
|
|
|
|
|
}
|
|
|
|
|
}
|
|
|
|
|
if(a1==1){
|
|
|
|
|
;
|
|
|
|
|
}else{
|
|
|
|
|
printf("没有这个项目的信息\n");
|
|
|
|
|
}
|
|
|
|
|
printf("********************\n");
|
|
|
|
|
}
|
|
|
|
|
void xxcz1(struct schoolform school[],int schoolgs){
|
|
|
|
|
printf("请输入你要查找的学校名称\n");
|
|
|
|
|
char name[20];
|
|
|
|
|
gets(name);
|
|
|
|
|
int i,a,a1=0;
|
|
|
|
|
for(i=0;i<schoolgs;i++){
|
|
|
|
|
a=strcmp(school[i].name,name);
|
|
|
|
|
if(a==0){
|
|
|
|
|
printf("将依次输出该学校信息：\n");
|
|
|
|
|
printf("名称：%s 编号：%s 参赛人数：%d 总分数：%s \n",school[i].name,school[i].id,school[i].number,school[i].scoer);
|
|
|
|
|
//printf("所属学校:%s 参加项目名称：%s 名次：%s 总分数：%d "，student[i].name1,student[i].xm.name,student[i].xm.mc,student.xm.score);
|
|
|
|
|
a1=1; //防止有些选手信息未记录而找不到
|
|
|
|
|
break;
|
|
|
|
|
}
|
|
|
|
|
}
|
|
|
|
|
if(a1==1){
|
|
|
|
|
;
|
|
|
|
|
}else{
|
|
|
|
|
printf("没有这个学校的信息\n");
|
|
|
|
|
}
|
|
|
|
|
printf("********************\n");
|
|
|
|
|
}
|
|
|
|
|
void xxcz2(struct schoolform school[],int schoolgs){
|
|
|
|
|
printf("请输入你要查找的学校编号\n");
|
|
|
|
|
char number[20];
|
|
|
|
|
gets(number);
|
|
|
|
|
int i,a,a1=0;
|
|
|
|
|
for(i=0;i<schoolgs;i++){
|
|
|
|
|
a=strcmp(school[i].id,number);
|
|
|
|
|
if(a==0){
|
|
|
|
|
printf("将依次输出该选学校信息：\n");
|
|
|
|
|
printf("名称：%s 编号：%s 参赛人数：%d 总分数：%s \n",school[i].name,school[i].id,school[i].number,school[i].scoer);
|
|
|
|
|
//printf("所属学校:%s 参加项目名称：%s 名次：%s 总分数：%d "，student[i].name1,student[i].xm.name,student[i].xm.mc,student.xm.score);
|
|
|
|
|
a1=1; //防止有些选手信息未记录而找不到
|
|
|
|
|
break;
|
|
|
|
|
}
|
|
|
|
|
}
|
|
|
|
|
if(a1==1){
|
|
|
|
|
;
|
|
|
|
|
}else{
|
|
|
|
|
printf("没有这个学校的信息\n");
|
|
|
|
|
}
|
|
|
|
|
printf("********************\n");
|
|
|
|
|
}
|
|
|
|
|
void schoolph(struct schoolform school[],int schoolgs){
|
|
|
|
|
int max=school[0].scoer;int maxnumber=0;
|
|
|
|
|
int ph[50];
|
|
|
|
|
int i,i1,t,t1;
|
|
|
|
|
t1=schoolgs;
|
|
|
|
|
for(i1=0;i1<schoolgs;i1++){
|
|
|
|
|
for(i=0;i<schoolgs;i++){
|
|
|
|
|
if(school[i].scoer>max){
|
|
|
|
|
max=school[i].scoer;
|
|
|
|
|
maxnumber=i;
|
|
|
|
|
}}
|
|
|
|
|
t=school[schoolgs-1].scoer;
|
|
|
|
|
school[schoolgs-1].scoer=max;
|
|
|
|
|
school[maxnumber].scoer=t;
|
|
|
|
|
schoolgs-=1;
|
|
|
|
|
ph[i1]=maxnumber;
|
|
|
|
|
}
|
|
|
|
|
printf("学校排行由高到低输出依次是：\n");
|
|
|
|
|
schoolgs=t1;
|
|
|
|
|
//printf("学校个数是%d\n",schoolgs);
|
|
|
|
|
for(i=0;i<schoolgs;i++){
|
|
|
|
|
printf("名称：%s 分数：%d\n",school[ph[i]].name,school[ph[i]].scoer);
|
|
|
|
|
}
|
|
|
|
|
printf("********************\n");
|
|
|
|
|
}
|
|
|
|
|
void studentph(struct studentform student[],int studentrs){
|
|
|
|
|
int max=student[0].xm.scoer;int maxnumber=0;
|
|
|
|
|
int ph[50];
|
|
|
|
|
int i,i1,t,t1;
|
|
|
|
|
t1=studentrs;
|
|
|
|
|
for(i1=0;i1<studentrs;i1++){
|
|
|
|
|
for(i=0;i<studentrs;i++){
|
|
|
|
|
if(student[i].xm.scoer>max){
|
|
|
|
|
max=student[i].xm.scoer;
|
|
|
|
|
maxnumber=i;
|
|
|
|
|
}}
|
|
|
|
|
t=student[studentrs-1].xm.scoer;
|
|
|
|
|
student[studentrs-1].xm.scoer=max;
|
|
|
|
|
student[maxnumber].xm.scoer=t;
|
|
|
|
|
studentrs-=1;
|
|
|
|
|
ph[i1]=maxnumber;
|
|
|
|
|
}
|
|
|
|
|
printf("学生排行由高到低输出依次是：\n");
|
|
|
|
|
studentrs=t1;
|
|
|
|
|
for(i=0;i<studentrs;i++){
|
|
|
|
|
printf("姓名：%s 分数：%d\n",student[ph[i]].name,student[ph[i]].xm.scoer);
|
|
|
|
|
}
|
|
|
|
|
printf("********************\n");
|
|
|
|
|
}
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
int main(){
|
|
|
|
|
printf("<<**********欢迎来到运动会比赛计分系统**********>>\n");
|
|
|
|
|
printf("此系统有以下功能选项：\n");
|
|
|
|
|
|
|
|
|
|
struct studentform student[50];
|
|
|
|
|
struct schoolform school[10];
|
|
|
|
|
struct xmform1 xm1[15];
|
|
|
|
|
struct xmform2 xm2[15];
|
|
|
|
|
int studentrs;
|
|
|
|
|
int schoolgs;
|
|
|
|
|
int xmgs1;
|
|
|
|
|
int xmgs2;
|
|
|
|
|
char name[10];
|
|
|
|
|
int a,a1,a2; //a2为方便switch退出时用的字符
|
|
|
|
|
int i;
|
|
|
|
|
//scanf("%d",&a);
|
|
|
|
|
do{
|
|
|
|
|
printf("输入选手信息（请按0)\n输入学校信息（请按1）\n输入项目信息（请按2）\n寻找并输出选手信息（请按3）\n寻找并输出项目信息（请按4）\n寻找并输出学校信息（请按5）\n学校排行输出（请按6）\n参赛选手排行输出（请按7）\n");
|
|
|
|
|
printf("退出（请按8）\n");
|
|
|
|
|
printf("********************\n");
|
|
|
|
|
scanf("%d",&a);
|
|
|
|
|
switch(a){
|
|
|
|
|
case 0:
|
|
|
|
|
//struct studentform student[50];
|
|
|
|
|
printf("你选择了输入选手信息功能\n");
|
|
|
|
|
//printf("共有多少位选手参赛？\n")
|
|
|
|
|
//int n;
|
|
|
|
|
//scanf("%d",&n);
|
|
|
|
|
studentrs=ggy(student);
|
|
|
|
|
break;
|
|
|
|
|
case 1:
|
|
|
|
|
//struct schoolform school[10];
|
|
|
|
|
printf("你选择了输入学校信息功能\n");
|
|
|
|
|
schoolgs=ggy1(school);
|
|
|
|
|
break;
|
|
|
|
|
case 2:
|
|
|
|
|
printf("你选择了输入项目信息功能\n");
|
|
|
|
|
printf("项目有两种一种取前五名，另一种取前三名。\n");
|
|
|
|
|
printf("开始第一类项目信息输入\n");
|
|
|
|
|
xmgs1=ggy2(xm1,student,school,schoolgs,studentrs);
|
|
|
|
|
printf("开始第二类项目信息输入\n");
|
|
|
|
|
xmgs2=ggy3(xm2,student,school,schoolgs,studentrs);
|
|
|
|
|
break;
|
|
|
|
|
case 3:
|
|
|
|
|
printf("你选择了寻找并输出选手信息的功能\n");
|
|
|
|
|
printf("有两种寻找方式 第一种根据选手姓名查找（按0） 第二种根据选手编号查找（按1） 请选择其中一种：\n");
|
|
|
|
|
scanf("%d",&a1);
|
|
|
|
|
getchar();
|
|
|
|
|
a2=1;
|
|
|
|
|
do{
|
|
|
|
|
switch(a1){
|
|
|
|
|
case 0:
|
|
|
|
|
printf("你选择了按选手姓名查找\n");
|
|
|
|
|
xscz(student,studentrs);
|
|
|
|
|
a2=0;
|
|
|
|
|
break;
|
|
|
|
|
case 1:
|
|
|
|
|
printf("你选择了根据选手编号查找\n");
|
|
|
|
|
xscz1(student,studentrs);
|
|
|
|
|
a2=0;
|
|
|
|
|
break;
|
|
|
|
|
default:
|
|
|
|
|
printf("请输入（0~1）以内的数\n");
|
|
|
|
|
scanf("%d",&a1);
|
|
|
|
|
getchar();
|
|
|
|
|
}
|
|
|
|
|
}while(a2);
|
|
|
|
|
break;
|
|
|
|
|
case 4:
|
|
|
|
|
printf("你选择了寻找并输出项目功能\n");
|
|
|
|
|
printf("有两种项目：第一类（分前五名）第二类（分前三名）,请选择你要查找那类项目的信息（第一类按0）（第二类按1）\n");
|
|
|
|
|
scanf("%d",&a1);
|
|
|
|
|
getchar();
|
|
|
|
|
a2=1;
|
|
|
|
|
do{
|
|
|
|
|
switch(a1){
|
|
|
|
|
case 0:
|
|
|
|
|
printf("你选择了按第一类查找\n");
|
|
|
|
|
xmcz1(xm1,xmgs1);
|
|
|
|
|
a2=0;
|
|
|
|
|
break;
|
|
|
|
|
case 1:
|
|
|
|
|
printf("你选择了按第二类查找\n");
|
|
|
|
|
xmcz2(xm2,xmgs2);
|
|
|
|
|
a2=0;
|
|
|
|
|
break;
|
|
|
|
|
default:
|
|
|
|
|
printf("请输入（0~1）以内的数\n");
|
|
|
|
|
scanf("%d",&a1);
|
|
|
|
|
getchar();
|
|
|
|
|
}
|
|
|
|
|
}while(a2);
|
|
|
|
|
break;
|
|
|
|
|
case 5:
|
|
|
|
|
printf("你选择了寻找并输出学校信息的功能\n");
|
|
|
|
|
printf("有两种寻找方式 第一种根据学校名称查找（按0） 第二种根据学校编号查找（按1） 请选择其中一种：\n");
|
|
|
|
|
scanf("%d",&a1);
|
|
|
|
|
getchar();
|
|
|
|
|
a2=1;
|
|
|
|
|
do{
|
|
|
|
|
switch(a1){
|
|
|
|
|
case 0:
|
|
|
|
|
printf("你选择了按学校名称查找\n");
|
|
|
|
|
xxcz1(school,schoolgs);
|
|
|
|
|
a2=0;
|
|
|
|
|
break;
|
|
|
|
|
case 1:
|
|
|
|
|
printf("你选择了根据学校编号查找\n");
|
|
|
|
|
xxcz2(school,schoolgs);
|
|
|
|
|
a2=0;
|
|
|
|
|
break;
|
|
|
|
|
default:
|
|
|
|
|
printf("请输入（0~1）以内的数\n");
|
|
|
|
|
scanf("%d",&a1);
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getchar();
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}
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}while(a2);
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break;
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case 6:
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printf("你选择了学校排行输出功能\n");
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schoolph(school,schoolgs);
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break;
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case 7:
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printf("你选择了参赛选手排行输出功能\n");
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studentph(student,studentrs);
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break;
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case 8:
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printf("成功退出，感谢使用！\n");
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return 0;
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default:
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printf("请按（0~8）以内的数字\n");
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}
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}while(1);
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return 0;
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}
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