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@ -194,10 +194,42 @@ $$A \to \begin{bmatrix} 1 & 1 & 3 & 1 & 0 & 1 \\ 0 & 1 & 1 & -1 & 1 & 2 \\ 0 & 2
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\underline{\qquad\qquad\qquad\qquad}.
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$$
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---
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解析:
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一眼顶针,鉴定为: $$
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x = (1,0,0,0)^T$$
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**答**:$(1,0,0,0)^T$。
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**解析**:由范德蒙行列式的性质可知 $|A| \neq 0$,从而线性方程组 $Ax = b$ 有唯一解。
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又由
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$$
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\begin{bmatrix}
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1 & a_1 & a_1^2 & a_1^3 \\
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1 & a_2 & a_2^2 & a_2^3 \\
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1 & a_3 & a_3^2 & a_3^3 \\
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1 & a_4 & a_4^2 & a_4^3
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\end{bmatrix}
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\begin{bmatrix}
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1 \\
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0 \\
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0 \\
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0
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\end{bmatrix}
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=
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\begin{bmatrix}
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1 \\
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1 \\
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1 \\
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1
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\end{bmatrix}
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$$
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可知 $Ax = b$ 的解为
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$$
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\begin{bmatrix}
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1 \\
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0 \\
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0 \\
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0
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\end{bmatrix}
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$$
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---
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