From 5a2d01374791f15fc757830398a458eb44ec26b0 Mon Sep 17 00:00:00 2001
From: Cym10x <Cym_em10x@outlook.com>
Date: Mon, 29 Dec 2025 10:52:28 +0800
Subject: [PATCH] =?UTF-8?q?=E5=90=88=E5=B9=B6?=
MIME-Version: 1.0
Content-Type: text/plain; charset=UTF-8
Content-Transfer-Encoding: 8bit

---
 素材/先化简再用洛必达.md     | 4 ----
 素材/洛必达法则-注意事项.md | 5 +++++
 2 files changed, 5 insertions(+), 4 deletions(-)
 delete mode 100644 素材/先化简再用洛必达.md

diff --git a/素材/先化简再用洛必达.md b/素材/先化简再用洛必达.md
deleted file mode 100644
index 1005062..0000000
--- a/素材/先化简再用洛必达.md
+++ /dev/null
@@ -1,4 +0,0 @@
----
-tags:
-  - 素材
----
diff --git a/素材/洛必达法则-注意事项.md b/素材/洛必达法则-注意事项.md
index aa9ab02..e3bd120 100644
--- a/素材/洛必达法则-注意事项.md
+++ b/素材/洛必达法则-注意事项.md
@@ -1,3 +1,8 @@
+---
+tags:
+  - 素材
+---
+
 1. 使用时需要在等号上方写明是用的什么类型的洛必达，$\frac{0}{0}$？$\frac{\infty}{\infty}$？
 	例如：$\lim\limits_{x\to\infty}\frac{\mathrm{e}^{2x}+1}{\mathrm{e}^{2x}-1} \overset{\frac{\infty}{\infty}}{=}\lim\limits_{x\to\infty}\frac{2\mathrm{e}^{2x}}{2\mathrm{e}^{2x}}=1$
 2. 适当使用洛必达，不要一直用洛必达，有时用等价无穷小化简更方便
\ No newline at end of file