@ -174,10 +174,24 @@ $$A^n = 6^{n-1}\begin{bmatrix}3&-1\\-9&3\end{bmatrix} $$
$$
\underline{\qquad\qquad\qquad\qquad}.
---
解析:
一眼顶针,鉴定为: $$
x = (1,0,0,0)^T$$
11.
A^{k} = 0
k= \underline{\qquad\qquad\qquad\qquad}.
12.