vault backup: 2025-12-29 21:29:15

develop
Elwood 4 months ago
parent 4e4e32d57d
commit e01b539f7c

@ -174,10 +174,24 @@ $$A^n = 6^{n-1}\begin{bmatrix}3&-1\\-9&3\end{bmatrix} $$
$$
\underline{\qquad\qquad\qquad\qquad}.
$$
---
解析:
一眼顶针,鉴定为: $$
x = (1,0,0,0)^T$$
---
11.
$$
A^{k} = 0
$$
$$
k= \underline{\qquad\qquad\qquad\qquad}.
$$
12.
$$
\underline{\qquad\qquad\qquad\qquad}.

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