diff --git a/padding_oracle_demo.py b/padding_oracle_demo.py
new file mode 100644
index 0000000..706028b
--- /dev/null
+++ b/padding_oracle_demo.py
@@ -0,0 +1,362 @@
+from Crypto.Cipher import AES
+from gmssl import func  # 该模块用于bytes与列表之间的转换
+
+
+# 密钥设置，请设置为16.24.32
+# ENCKEY = '1234567812345678'
+
+def po_main(plain=None, iv=None, enckey=None, attacker_enc=None, plain_want=None):
+    """
+    函数作用：主函数，用于基本信息的输入和整体提示信息的输出
+            调用其他函数完成攻击流程
+    """
+    print("=== Padding Oricle Attrack POC(CBC-MODE) ===")
+
+    # 服务端默认设置
+    cipher = "aes"  # 加密方式（当前代码只支持AES)
+    block_size = 16  # 分组大小（AES默认为16）
+
+    # 测试设置(实际使用时请注释掉)
+    # iv = "1234567812345678".encode('utf-8')            # 初始向量
+    # plain = "111111111111111122222".encode('utf-8')    # 明文
+    # plain_want = "opaas".encode('utf-8')               # 想要获取密文的明文
+
+    iv = iv.encode('utf-8')
+    # 判断IV是否长度是否符合要求
+    if len(iv) != block_size:
+        print("[-] IV must be" + str(block_size) + "bytes long!")
+        return False
+
+    if plain:
+        plain = plain.encode('utf-8')
+
+        print("=== Generate Target Ciphertext ===")
+        # 调用函数加密
+        ciphertext = encrypt(plain, iv, cipher, enckey)
+        if not ciphertext:
+            print("[-] Encrypt Error!")
+            return False
+
+        # 输出一些基本信息
+        print("[+] plaintext is: " + str(plain, encoding="utf-8"))
+        print("[+] iv is: ", iv.decode("utf-8"))
+        print("[+] ciphertext is: ", ciphertext)
+
+        return ciphertext
+
+    if attacker_enc:
+        print(attacker_enc)
+        print(type(attacker_enc))
+
+    if plain_want:
+        plain_want = plain_want.encode('utf-8')
+
+    # 开始进行Padding Oracle攻击
+    print("=== Start Padding Oracle Decrypt ===")
+    print("[+] Choosing Cipher: " + cipher.upper())
+    guess = padding_oracle_decrypt(cipher, attacker_enc, iv, block_size=block_size, enckey=enckey)
+    if guess:
+        print("[+] Guess intermediary value is: ", guess["intermediary"])
+        print("[+] plaintext = intermediary_value XOR original_IV")
+        print("[+] Guess plaintext is: ", guess["plaintext"])
+
+        # 开始利用获取的中间值求解指定明文加密后的密文
+        if plain_want:
+            print("=== Start Padding Oracle Encrypt ===")
+            print("[+] plaintext want to encrypt is: ", plain_want)
+            print("[+] Choosing Cipher: " + cipher.upper())
+            en = padding_oracle_encrypt(cipher, attacker_enc, plain_want, iv, block_size=block_size, enckey=enckey)
+            if en:
+                print("[+] Encrypt Success!")
+                print("[+] The ciphertext you want is: ", en[block_size:])
+                print("[+] IV is: ", iv)
+                print("=== Let's verify the custom encrypt result ===")
+                print("[+] Decrypt of ciphertext ", en[block_size:], " is:")
+                de = decrypt(en[block_size:], en[:block_size], cipher, enckey)
+                if de == add_PKCS5_padding(plain_want, block_size):
+                    print(de)
+                    print("[+] Bingo!")
+
+                else:
+                    print("[-] It seems something wrong happened!")
+                    return False
+        return guess["plaintext"], en[block_size:]
+
+    else:
+        return False
+
+
+def padding_oracle_encrypt(cipher, ciphertext, plaintext, iv, enckey, block_size=16):
+    """"
+    函数功能：完成指定明文加密的功能
+    输入：
+        cipher:加密类型
+        ciphertext:已知的密文
+        plaintext:需要加密的明文
+        iv:初始向量
+        block_size:分组大小
+    输出：
+        guess_cipher：猜测的密文（包含IV和密文）
+    注意：这个函数功能的实现是在前面攻击的基础上实现的，即已经获取到了中间值
+    """
+
+    guess_cipher = ciphertext[0 - block_size:]
+
+    plaintext = add_PKCS5_padding(plaintext, block_size)
+
+    print("[*] After padding, plaintext becomes to: ", plaintext)
+
+    block = len(plaintext)
+
+    iv_nouse = iv  # 用不到，只需要中间值
+
+    prev_cipher = ciphertext[0 - block_size:]  # init with the last cipher block
+
+    while block > 0:
+        tmp = padding_oracle_decrypt_block(cipher, prev_cipher, iv_nouse, block_size=block_size, debug=False, enckey=enckey)
+        prev_cipher = xor_str(plaintext[block - block_size:block], tmp["intermediary"])
+        guess_cipher = prev_cipher + guess_cipher.decode(encoding="ISO-8859-1")
+        block = block - block_size
+    guess_cipher = guess_cipher.encode(encoding="ISO-8859-1")
+    return guess_cipher
+
+
+# 一个简单的异或操作，用于求解明文
+def xor(first, second):
+    return bytearray(x ^ y for x, y in zip(first, second))
+
+
+def padding_oracle_decrypt(cipher, ciphertext, iv, enckey, block_size=8, debug=True):
+    """"
+    函数功能：对密文进行分组，并调用函数攻击每一个分组以获取中间值
+    输入：
+        cipher:加密类型
+        ciphertext:已知的密文
+        iv:初始向量
+        block_size:分组大小
+    输出：
+        result：获取的中间值和明文信息
+    注意：这个函数不是主要的攻击函数，而是完成分组和调用攻击函数的功能
+    """
+
+    # 将密文进行分组
+    cipher_block = split_cipher_block(ciphertext, block_size)
+
+    if cipher_block:
+        result = {}
+        result["intermediary"] = ''
+        result["plaintext"] = ''
+        counter = 0
+        for c in cipher_block:
+            if debug:
+                print("[*] Now try to decrypt block " + str(counter))
+                print("[*] Block " + str(counter) + "'s ciphertext is: ", c)
+
+            # 调用真正的攻击函数（每一次攻击一个分组）
+            guess = padding_oracle_decrypt_block(cipher, c, iv, block_size=block_size, debug=debug, enckey=enckey)
+
+            if guess:
+                iv = c
+                guess_inter = guess["intermediary"].decode(encoding="ISO-8859-1")
+                result["intermediary"] += guess_inter
+                guess_plain = guess["plaintext"].decode(encoding="ISO-8859-1")
+                result["plaintext"] += guess_plain
+                if debug:
+                    print("[+] Block " + str(counter) + " decrypt!")
+                    print("[+] intermediary value is: ", guess["intermediary"])
+                    print("[+] The plaintext of block " + str(counter) + " is: ", guess["plaintext"])
+                counter = counter + 1
+            else:
+                print("[-] padding oracle decrypt error!")
+                return False
+        # 返回值的格式要进行转换
+        result["intermediary"] = result["intermediary"].encode(encoding="ISO-8859-1")
+        result["plaintext"] = result["plaintext"].encode(encoding="ISO-8859-1")
+        return result
+    else:
+        print("[-] ciphertext's block_size is incorrect!")
+        return False
+
+
+def padding_oracle_decrypt_block(cipher, ciphertext, iv, enckey, block_size=16, debug=True):
+    """"
+    函数功能：对单个分组进行攻击。获取中间值和明文
+    输入：
+        cipher:加密类型
+        ciphertext:已知的密文（分组）
+        iv:初始向量
+        block_size:分组大小
+    输出：
+        result：获取的中间值和明文信息（单个分组）
+    注意：这个函数不是主要的攻击函数，而是完成分组和调用攻击函数的功能
+    """
+    result = {}
+    intermediary = bytearray(16)  # 中间值
+
+    iv_p = bytearray(16)  # 用于猜测的IV向量
+
+    # 通过for循环实现猜测的功能
+    for i in range(1, block_size + 1):
+        for b in range(0, 256):
+            iv_p[16 - i] = b
+            iv_bytes = bytes(iv_p)
+            plain = decrypt(ciphertext, iv_bytes, cipher, enckey)
+
+            # 最关键的一步，用于模拟服务器的回显，即padding是否符合要求
+            if check_PKCS5_padding(plain, i):
+                if debug:
+                    print("[*] Try IV: ", func.bytes_to_list(iv_bytes))
+                    print("[*] Found padding oracle: ", hex_s(plain))
+                intermediary[16 - i] = i ^ b
+        for m in range(1, i + 1):
+            iv_p[16 - m] = (i + 1) ^ intermediary[16 - m]
+    plain = xor(iv, intermediary)
+    result["plaintext"] = plain
+    result["intermediary"] = bytes(intermediary)
+    return result
+
+
+# 一个简单的分组函数
+def split_cipher_block(ciphertext, block_size=8):
+    if len(ciphertext) % block_size != 0:
+        return False
+    result = []
+    length = 0
+    while length < len(ciphertext):
+        # 每一个分组都是一个字符串
+        result.append(ciphertext[length:length + block_size])
+        length += block_size
+    return result
+
+
+def check_PKCS5_padding(plain, p):
+    """"
+    函数功能：服务器回显判断
+    输入：
+        plain:明文
+        p:正在猜测的位数
+    输出：
+        True or False
+    注意：这个函数用于模拟服务端，给出回显
+    """
+    if len(plain) % 16 != 0:
+        return False
+
+    # 字符串反向，为了下面便于比较
+    plain = plain[::-1]
+    ch = 0
+    found = 0  # 相等的位数
+
+    while ch < p:
+        if bytes(plain[ch]) == bytes(p):
+            found += 1
+        ch += 1
+
+    if found == p:
+        return True
+    else:
+        return False
+
+
+def add_PKCS5_padding(plaintext, block_size):
+    """"
+    函数功能：PKCS5填充
+    输入：
+        plaintext:明文
+        block_size:分组大小
+    输出：
+        plaintext：填充后的明文
+    注意：这个函数用于填充缺失值，是本次攻击可以实施的本源
+    """
+    s = ''
+
+    if len(plaintext) % block_size == 0:
+        return plaintext
+
+    if len(plaintext) < block_size:
+        padding = block_size - len(plaintext)
+
+    else:
+        padding = block_size - (len(plaintext) % block_size)
+    plaintext = str(plaintext, encoding="utf-8")
+    for i in range(0, padding):
+        plaintext += chr(padding)
+    plaintext = bytes(plaintext, encoding="utf-8")
+    return plaintext
+
+
+def decrypt(ciphertext, iv, cipher, enckey):
+    """"
+    函数功能：解密密文（AES)
+    输入：
+        ciphertext:密文
+        iv:初始向量
+        cipher:加解密方式
+    输出：
+        o.decrypt(ciphertext)：解密后的明文
+    注意：这个函数在本次实验里主要是用于验证密文的有效性
+    """
+
+    key = enckey
+    if cipher.lower() == "aes":
+        o = AES.new(key, AES.MODE_CBC, iv)
+    else:
+        return False
+
+    if len(iv) % 16 != 0:
+        return False
+
+    if len(ciphertext) % 16 != 0:
+        return False
+
+    return o.decrypt(ciphertext)
+
+
+def encrypt(plaintext, iv, cipher, enckey):
+    """"
+    函数功能：加密明文（AES)
+    输入：
+        plaintext:明文
+        iv:初始向量
+        cipher:加解密方式
+    输出：
+        o.encrypt(plaintext)：加密后的密文
+    注意：这个函数在本次实验里主要是用于初始服务端加密以获取到密文
+    """
+    key = enckey
+
+    if cipher.lower() == "aes":
+
+        if len(key) != 16 and len(key) != 24 and len(key) != 32:
+            print("[-] AES key must be 16/24/32 bytes long!")
+            return False
+
+        o = AES.new(key, AES.MODE_CBC, iv)
+    else:
+        return False
+
+    plaintext = add_PKCS5_padding(plaintext, len(iv))
+    return o.encrypt(plaintext)
+
+
+# 这个函数主要用于第二段攻击时某个值的计算
+def xor_str(a, b):
+    if len(a) != len(b):
+        return False
+
+    c = []
+    for i in range(0, len(a)):
+        c.append(a[i] ^ b[i])
+    c = bytes(c)
+    return c.decode(encoding="ISO-8859-1")
+
+
+# 可有可无
+def hex_s(str2):
+    re = []
+    re = func.bytes_to_list(str2)
+    return re
+
+
+if __name__ == "__main__":
+    po_main()