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步骤四.cpp

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+#include <stdio.h>
+#include <stdlib.h>
+#include <time.h>
+#include <arm_neon.h>
+
+#define SIZE 1024
+
+// 基础矩阵乘法函数
+void matmul(float A[SIZE][SIZE], float B[SIZE][SIZE], float C[SIZE][SIZE], int n) {
+    for (int i = 0; i < n; i++) {
+        for (int j = 0; j < n; j++) {
+            float sum = 0;
+            for (int k = 0; k < n; k++) {
+                sum += A[i][k] * B[k][j];
+            }
+            C[i][j] = sum;
+        }
+    }
+}
+
+// NEON优化的矩阵乘法函数
+void matmul_optimized(float A[SIZE][SIZE], float B[SIZE][SIZE], float C[SIZE][SIZE], int n) {
+    int i, j, k;
+    for (i = 0; i < n; i++) {
+        for (j = 0; j < n; j += 4) {
+            float32x4_t sum = vdupq_n_f32(0);
+            for (k = 0; k < n; k++) {
+                float32x4_t a = vld1q_f32(&A[i][k]); // Load 4 elements from A
+                float32x4_t b = vld1q_f32(&B[k][j]); // Load 4 elements from B
+                sum = vmlaq_f32(sum, a, b); // Multiply and accumulate
+            }
+            vst1q_f32(&C[i][j], sum); // Store the result
+        }
+    }
+}
+
+int main() {
+    // 矩阵内存分配
+    float (*A)[SIZE] = malloc(SIZE * SIZE * sizeof(float));
+    float (*B)[SIZE] = malloc(SIZE * SIZE * sizeof(float));
+    float (*C)[SIZE] = malloc(SIZE * SIZE * sizeof(float));
+
+    if (A == NULL || B == NULL || C == NULL) {
+        printf("Memory allocation failed!\n");
+        return 1;
+    }
+
+    // 初始化矩阵数据
+    srand(time(NULL)); // 初始化随机数种子
+    for (int i = 0; i < SIZE; i++) {
+        for (int j = 0; j < SIZE; j++) {
+            A[i][j] = rand() % 100;
+            B[i][j] = rand() % 100;
+        }
+    }
+
+
+    for (int i = 0; i < SIZE; i++) {
+        for (int j = 0; j < SIZE; j++) {
+            C[i][j] = 0;
+        }
+    }
+
+    // 计时并输出基础矩阵乘法的运行时间
+    clock_t start, end;
+    start = clock();
+    matmul(*A, *B, *C, SIZE);
+    end = clock();
+    double time_spent = (double)(end - start) / CLOCKS_PER_SEC;
+    printf("基础矩阵乘法的运行时间为: %lf 秒\n", time_spent);
+
+
+    for (int i = 0; i < SIZE; i++) {
+        for (int j = 0; j < SIZE; j++) {
+            C[i][j] = 0;
+        }
+    }
+
+    // 计时并输出NEON优化矩阵乘法的运行时间
+    start = clock();
+    matmul_optimized(*A, *B, *C, SIZE);
+    end = clock();
+    time_spent = (double)(end - start) / CLOCKS_PER_SEC;
+    printf("NEON优化矩阵乘法的运行时间为: %lf 秒\n", time_spent);
+
+
+    free(A);
+    free(B);
+    free(C);
+
+    return 0;
+}