# -*- encoding: utf-8 -*- """ @Author: packy945 @FileName: data.py @DateTime: 2023/5/11 14:36 @SoftWare: PyCharm """ from itertools import permutations import random import tkinter as tk MARK = '#ff0000' NOMARK = '#cccccc' class Aexp: def __init__(self, a, b, c, d): self.Aexp_cur = 0 self.num = 0 self.card = [a, b, c, d] # print(self.card) self.answer = [] self.Color = [] self.Aexp(a, b, c, d) def refresh(self, a, b, c, d): self.Aexp_cur = 0 self.num = 0 self.card = [a, b, c, d] # print(self.card) self.answer = [] self.Color = [] self.Aexp(a, b, c, d) def Aexp(self, one, two, three, four): ''' 输入四个数,求24点 :param one: :param two: :param three: :param four: :return: 求解24点结果。若无法得出则返回“无法求得结果” ''' self.Aexp_cur = 0 my_list = [one, two, three, four] result = [c for c in permutations(my_list, 4)] list2 = [] # 算出24的排列组合的列表 symbols = ["+", "-", "*", "/"] flag = False for one, two, three, four in result: for s1 in symbols: for s2 in symbols: for s3 in symbols: express = ["(({0}{1}{2}){3}{4}){5}{6}".format(one[1], s1, two[1], s2, three[1], s3, four[1]), "({0}{1}{2}){3}({4}{5}{6})".format(one[1], s1, two[1], s2, three[1], s3, four[1]), "({0}{1}({2}{3}{4})){5}{6}".format(one[1], s1, two[1], s2, three[1], s3, four[1]), "{0}{1}(({2}{3}{4}){5}{6})".format(one[1], s1, two[1], s2, three[1], s3, four[1]), "{0}{1}({2}{3}({4}{5}{6}))".format(one[1], s1, two[1], s2, three[1], s3, four[1])] # if str(one) + str(two) + str(three) + str(four) == "8383": # print(express) for e in express: try: if round(eval(e), 6) == 24: e = del_parentheses(e) list2.append(e) self.Color.append([one[0], two[0], three[0], four[0]]) flag = True except ZeroDivisionError: pass if flag: self.answer = list2 self.num = len(list2) # return list3 else: self.answer = ["无法得出24点"] self.Color.append(None) self.num = 0 #删除最外层括号 def del_parentheses(e): if e[0] == '(' and e[-1] == ')': try: eval(e[1:len(e)-1]) except: pass else: if round(eval(e[1:len(e)-1]),6) == 24: return e[1:len(e)-1] return e