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pgftvecou 3 years ago
parent 4fc472e86e
commit df3b994722

@ -0,0 +1,17 @@
//斐波拉契//求第几项的数
#include<stdio.h>
int Fibon1(int n){
if (n == 1 || n == 2) {
return 1;
} else {
return Fibon1(n - 1) + Fibon1(n - 2);
}
}
int main(){
int n = 0;
int ret = 0;
scanf("%d", &n);
ret = Fibon1(n);
printf("ret=%d",ret);
return 0;
}
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