[sledge] Remove eliminated existentials from equality relations

Summary:
Currently there is an implicit assumption in Sh.simplify that
variables do not occur free in an equality relation which makes no
constraint on their values. This diff adds a step to formula
simplification that explicitly removes eliminated existentials from
equality relations.

Reviewed By: jvillard

Differential Revision: D20726960

fbshipit-source-id: 7109aa479
master
Josh Berdine 5 years ago committed by Facebook GitHub Bot
parent 30c23f8cd6
commit 2aacc03880

@ -52,6 +52,7 @@ module Subst : sig
val compose : t -> t -> t
val compose1 : key:Term.t -> data:Term.t -> t -> t
val extend : Term.t -> t -> t option
val remove : Var.Set.t -> t -> t
val map_entries : f:(Term.t -> Term.t) -> t -> t
val to_alist : t -> (Term.t * Term.t) list
val partition_valid : Var.Set.t -> t -> t * Var.Set.t * t
@ -109,6 +110,10 @@ end = struct
| exception Found -> None
| s -> Some s
(** remove entries for vars *)
let remove xs s =
Var.Set.fold ~f:(fun s x -> Term.Map.remove s (Term.var x)) ~init:s xs
(** map over a subst, applying [f] to both domain and range, requires that
[f] is injective and for any set of terms [E], [f\[E\]] is disjoint
from [E] *)
@ -1016,6 +1021,8 @@ let solve_for_vars vss r =
else Continue us_xs )
~finish:(fun _ -> false) ) )]
let elim xs r = {r with rep= Subst.remove xs r.rep}
(* Replay debugging *)
type call =

@ -102,6 +102,10 @@ val solve_for_vars : Var.Set.t list -> t -> Subst.t
to terms [e] with free variables contained in as short a prefix of [uss]
as possible. *)
val elim : Var.Set.t -> t -> t
(** Weaken relation by removing oriented equations [k ↦ _] for [k] in
[ks]. *)
(* Replay debugging *)
val replay : string -> unit

@ -725,17 +725,19 @@ let remove_absent_xs ks q =
if Var.Set.is_empty ks then q
else
let xs = Var.Set.diff q.xs ks in
let cong = Equality.elim ks q.cong in
let djns =
let rec trim_ks ks djns =
List.map djns ~f:(fun djn ->
List.map djn ~f:(fun sjn ->
{ sjn with
us= Var.Set.diff sjn.us ks
; cong= Equality.elim ks sjn.cong
; djns= trim_ks ks sjn.djns } ) )
in
trim_ks ks q.djns
in
{q with xs; djns}
{q with xs; cong; djns}
let rec simplify_ us rev_xss q =
[%Trace.call fun {pf} -> pf "%a@ %a" pp_vss (List.rev rev_xss) pp_raw q]

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