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101 lines
2.3 KiB
101 lines
2.3 KiB
#include <stdio.h>
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#include <stdlib.h>
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#include <time.h>
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void assignNumbers(int matrix[3][9])
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{
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srand(time(NULL));
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int num[10]={0,1,2,3,4,5,6,7,8,9};
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for (int i = 0; i < 3; i++)
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{
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for (int j = 0; j < 3; j++)
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{
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int randomNumber = rand() % 10;
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int random=rand()%10;
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while (matrix[i][randomNumber] != 0)
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{
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randomNumber = rand() % 10;
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}
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while(num[random]==10)
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{
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random=rand()%10;
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}
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matrix[i][randomNumber] =num[random] ;
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num[random]=10;
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}
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}
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}
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void shuffleMatrix(int matrix[3][9])//洗牌算法
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{
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for (int i = 2; i >= 0; i--)
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{
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for (int j = 8; j > 0; j--)
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{
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int row1 = i;
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int col1 = j;
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int row2 = rand() % (i + 1);
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int col2 = rand() % (j + 1);
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int temp = matrix[row1][col1];
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matrix[row1][col1] = matrix[row2][col2];
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matrix[row2][col2] = temp;
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}
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}
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}
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void mergeMatrices(int matrix1[3][9], int matrix2[3][9], int matrix3[3][9], int mergedMatrix[9][9]) //合并矩阵
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{
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// 复制第一个矩阵的内容到前三行
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for (int i = 0; i < 3; i++) {
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for (int j = 0; j < 9; j++) {
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mergedMatrix[i][j] = matrix1[i][j];
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}
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}
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// 复制第二个矩阵的内容到中间三行
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for (int i = 0; i < 3; i++) {
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for (int j = 0; j < 9; j++) {
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mergedMatrix[i + 3][j] = matrix2[i][j];
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}
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}
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// 复制第三个矩阵的内容到最后三行
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for (int i = 0; i < 3; i++) {
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for (int j = 0; j < 9; j++) {
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mergedMatrix[i + 6][j] = matrix3[i][j];
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}
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}
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}
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void print(int board[9][9])
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{
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for (int i = 0; i < 9; i++) //行
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{
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if (i % 3 == 0 )
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{
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printf("---------------------\n");
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}
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for (int j = 0; j < 9; j++) //列
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{
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if (j % 3 == 0 && j != 0)
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{
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printf("| ");
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}
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printf("%d ", board[i][j]);
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}
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printf("\n");
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}
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}
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int main()
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{
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int merge[9][9]={0};
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int mat1[3][9]={0};
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int mat2[3][9]={0};
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int mat3[3][9]={0};
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assignNumbers(mat1);
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assignNumbers(mat2);
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assignNumbers(mat3);
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mergeMatrices(mat1,mat2,mat3,merge);
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print(merge);
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return 0;
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}
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