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@ -71,63 +71,4 @@ void ShortestPath(MatGrath &G,int v,int w)//求两点之间的最短路径
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功能:用Dijkstra算法求给出的一点到其余个点的最短路径
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输入:源点
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输出:地点的最短路程以及路径
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***********************/
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//Dijkstra算法求单源路径
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int Ppath2(MatGrath &G,int path[],int i,int v) //前向递归查找路径上的顶点
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{
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int k;
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k=path[i];
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if (k==v) return k; //找到了起点则返回
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Ppath2(G,path,k,v); //找顶点k的前一个顶点
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printf("%s->",G.vexs[k].sight);//输出顶点k
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}
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void danyuan(MatGrath &G,int v)//求两点之间的最短路径
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{
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int dist[MAXV],path[MAXV];
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int s[MAXV];
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int mindis,i,j,u;
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for (i=1; i<=G.vexnum; i++)
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{
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dist[i]=G.arc[v][i].length; //距离初始化
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s[i]=0; //s[]置空
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if (G.arc[v][i].length<INF) //路径初始化
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path[i]=v;
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else
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path[i]=-1;
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}
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s[v]=1;
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path[v]=0; //源点编号v放入s中
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for (i=1; i<=G.vexnum; i++) //循环直到所有顶点的最短路径都求出
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{
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mindis=INF; //mindis置最小长度初值
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for (j=1; j<=G.vexnum; j++) //选取不在s中且具有最小距离的顶点u
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if (s[j]==0 && dist[j]<mindis)
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{
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u=j;
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mindis=dist[j];
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}
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s[u]=1; //顶点u加入s中
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for (j=1; j<=G.vexnum; j++) //修改不在s中的顶点的距离
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if (s[j]==0)
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if (G.arc[u][j].length<INF && dist[u]+G.arc[u][j].length<dist[j])
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{
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dist[j]=dist[u]+G.arc[u][j].length;
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path[j]=u;
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}
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}
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for(i=1; i<=G.vexnum; i++)
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if (s[i]==1&&v!=i)
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{
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printf(" 从%s到%s的最短路径长度为:%d米\t路径为:",G.vexs[v].sight,G.vexs[i].sight,dist[i]);
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printf("%s->",G.vexs[v].sight); //输出路径上的起点
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Ppath2(G,path,i,v); //输出路径上的中间点
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printf("%s\n",G.vexs[i].sight); //输出路径上的终点
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}
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}
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***********************/
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