From 58c776b49f1ebf82fedaf25d4e9ed43ec2eee18b Mon Sep 17 00:00:00 2001
From: unknown <18951088369@163.com>
Date: Wed, 31 Dec 2025 00:21:35 +0800
Subject: [PATCH] vault backup: 2025-12-31 00:21:35

---
 编写小组/试卷/1231线性代数考试卷.md | 2 +-
 1 file changed, 1 insertion(+), 1 deletion(-)

diff --git a/编写小组/试卷/1231线性代数考试卷.md b/编写小组/试卷/1231线性代数考试卷.md
index 8998026..f3cbb24 100644
--- a/编写小组/试卷/1231线性代数考试卷.md
+++ b/编写小组/试卷/1231线性代数考试卷.md
@@ -64,7 +64,7 @@ tags:
 0 & 0 & 0 & \cdots & 0 & 0 & 0 & \cdots & 0 & 0 & 0 \\
 0 & 0 & 0 & \cdots & 0 & 0 & 0 & \cdots & 0 & 0 & 0 \\
 0 & 0 & 0 & \cdots & 0 & 0 & 0 & \cdots & 0 & 0 & 0 
-\end{bmatrix}_{n \times n}$$其中第一行有$m$个$0$.若$A^k=O$,则$k$的最小值为$\underline{\qquad\qquad\qquad\qquad}.$
+\end{bmatrix}_{(nm) \times (nm)}$$其中第一行有$m$个$0$.若$A^k=O$,则$k$的最小值为$\underline{\qquad\qquad\qquad\qquad}.$
 
 12. 设 $A, B$ 均为 $n$ 阶方阵，满足$\text{rank} \begin{bmatrix} A \\ B \end{bmatrix} = \text{rank}B,$ 且方程 $XA = B$ 有解。若 $\operatorname{rank} A = k$，则$\text{rank} \begin{bmatrix} A & O \\ B & E \end{bmatrix} =\underline{\hspace{3cm}}.$