@ -77,7 +77,7 @@ $$
则 $P^{-1}ABP = P^{-1}BAP$
$$
\therefore P^{-1}APP^{-1}BP = P^{-1}BPP^{-1}APP
\therefore P^{-1}APP^{-1}BP = P^{-1}BPP^{-1}AP
设 $P^{-1}BP = \Lambda_2$