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113 lines
2.0 KiB
113 lines
2.0 KiB
#include <stdio.h>
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int main ( )
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{
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int i,j,number,s,q,p,t,g;
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printf("“The original Sudoku matrix:");
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printf("\n");
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char board[9][9]={{'5','3','4','6','7','8','9','2','1'},
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{'6','7','2','1','9','5','3','4','6'},
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{'1','9','8','3','4','2','5','8','7'},
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{'8','5','9','7','6','1','4','2','3'},
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{'4','2','6','8','5','3','7','9','1'},
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{'7','1','3','9','2','4','8','5','6'},
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{'9','6','1','5','3','7','2','8','4'},
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{'2','8','7','4','1','9','6','3','5'},
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{'3','4','5','2','8','6','1','7','9'}};
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for (i=0;i<9;i++)
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{
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for (j=0;j<9;j++)
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{
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printf(" %c ",board[i][j]);
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}
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printf("\n");
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}
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//此处引入1
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int c[10]={0,0,0,0,0,0,0,0,0,0};//用来储存数字出现的个数
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//下面小矩阵的判断
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int w[10]={1,2,3,4,5,6,7,8,9};
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int k=0;
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for(t=3;t<=9;t=t+3)
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{
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for(g=3;g<=9;g=g+3)
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{
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for(i=t-3;i<t;i++)
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{
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for(j=g-3;j<g;j++)//分出来小矩阵
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{
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for(number=1;number<=9;number++)
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{
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if(board[i][j]==number+'0')
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{c[number]++;}
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}
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}
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}
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for(q=1;q<=9;q++)
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{
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if(c[q]>1)
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{
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printf("False:Invalid initial Sudoku matrix!");
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printf("The number %d in the block %d has been used!",q,w[k]);
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return 0;
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}
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}
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k++;
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for(s=0;s<=9;s++)c[s]=0;
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}
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}
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//完成行的判断
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for(i=0;i<9;i++)
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{
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for(number=1;number<=9;number++)
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{
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for(j=0;j<9;j++)
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{
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if(board[i][j]==number+'0')
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c[number]++;
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}
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}
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for(q=1;q<=9;q++)
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{
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if(c[q]>1)
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{
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printf("False:Invalid initial Sudoku matrix!\n");
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printf("The number %d in the col %d has been used!",q,i+1);
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return 0 ;
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}
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}
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for(p=0;p<10;p++)
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{
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c[p]=0;
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}
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}
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//同理列的判断
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for(i=0;i<9;i++)
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{
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for(number=1;number<=9;number++)
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{
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for(j=0;j<9;j++)
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{
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if(board[j][i]==number+48)
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c[number]++;}
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}
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for(q=1;q<=9;q++)
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{
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if(c[q]>1)
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{
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printf("False:Invalid initial Sudoku matrix!");
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printf("The number %d in the column %d has been used!",q,i+1);
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return 0;
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}
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}
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for(p=0;p<10;p++)
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{
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c[p]=0;
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}
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}
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return 0;
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}
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