#include // 输出矩阵的格式化结果 void printarr(int arr[9][9]) { int i,j,k,n; for(n=0;n<=6;n=n+3) { printf("|-----------------------|\n") ; for(i=n;i<=n+2;i++) { for(k=0;k<=6;k=k+3) { printf("|"); for(j=k;j<=k+2;j++) { printf(" %d",arr[i][j]); } printf(" "); } printf("|\n"); } } printf("|-----------------------|\n") ; } const char* checkSudoku(int matrix[9][9]) { // 检查每一行 for (int i = 0; i < 9; i++) { int seen[10] = {0}; for (int j = 0; j < 9; j++) { int num = matrix[i][j]; if (num != 0) { if (seen[num] != 0) { printf("False:Invalid initial Sudoku matrix!\nThe number %d in the row %d has been used!",num,i+1); return 0; } seen[num] = 1; } } } // 检查每一列 for (int j = 0; j < 9; j++) { int seen[10] = {0}; for (int i = 0; i < 9; i++) { int num = matrix[i][j]; if (num != 0) { if (seen[num] != 0) { printf("False:Invalid initial Sudoku matrix!\nThe number %d in the col %d has been used!",num,j+1); return 0; } seen[num] = 1; } } } // 检查每个 3x3 子矩阵 for (int block = 0; block < 9; block++) { int seen[10] = {0}; int startRow = (block / 3) * 3; int startCol = (block % 3) * 3; for (int i = startRow; i < startRow + 3; i++) { for (int j = startCol; j < startCol + 3; j++) { int num = matrix[i][j]; if (num != 0) { if (seen[num] != 0) { printf("False:Invalid initial Sudoku matrix!\nThe number %d in the block %d has been used!",num,block+1); return 0; } seen[num] = 1; } } } } return "True:Valid initial Sudoku matrix!"; } int main() { int sudokuMatrix[9][9] = { {3, 3, 0, 0, 7, 0, 0, 0, 0}, {6, 0, 0, 1, 9, 5, 0, 0, 0}, {0, 9, 8, 0, 0, 0, 0, 6, 0}, {8, 0, 0, 0, 6, 0, 0, 0, 3}, {4, 0, 0, 8, 0, 3, 0, 0, 1}, {7, 0, 0, 0, 2, 0, 0, 0, 6}, {0, 6, 0, 0, 0, 0, 2, 8, 0}, {0, 0, 0, 4, 1, 9, 0, 0, 5}, {0, 0, 0, 0, 8, 0, 0, 7, 9} }; // 输出原始数独矩阵 printf("The original Sudoku matrix: \n"); printarr(sudokuMatrix); // 判断数独矩阵是否合法 const char* result = checkSudoku(sudokuMatrix); printf("%s\n", result); return 0; }