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9×9 数组格式化输出.c

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+#include<stdio.h>
+int i,n,j,k;
+int main()
+{
+	int a[9][9]={{5,3,4,6,7,8,9,1,2},
+	{6,7,2,1,9,5,3,4,8},
+	{1,9,8,3,4,2,5,6,7},
+	{8,5,9,7,6,1,4,2,3},
+	{4,2,6,8,5,3,7,9,1},
+	{7,1,3,9,2,4,8,5,6},
+	{9,6,1,5,3,7,2,8,4},
+	{2,8,7,4,1,9,6,3,5},
+	{3,4,5,2,8,6,1,7,9}};
+	for(i=0;i<9;i++)
+	{
+		printf("|");
+		if(i==0||i==3||i==6)
+		{
+			for(k=0;k<23;k++)
+			printf("-");
+			printf("|\n|");
+		}
+		printf(" ");
+		for(j=0;j<9;j++)
+		{
+			if(j==2||j==5) 
+			printf("%d | ",a[i][j]);
+			else
+			printf("%d ",a[i][j]);
+		}
+		printf("|\n");
+	}
+	printf("|");
+	for(k=0;k<23;k++)
+	printf("-");
+	printf("|\n");
+} 
+