csv convert to xlsx

dev-clawer
Lin 1 month ago
parent 3eecc9ed60
commit 1c9ec9b167

@ -0,0 +1,73 @@
import pandas as pd
import os
from datetime import datetime, timedelta
def get_departure_destination(file_name):
name_without_extension = os.path.splitext(file_name)[0]
return name_without_extension
def merge_csv_files(csv_files, output_xlsx):
all_dfs = []
for csv_file in csv_files:
df = pd.read_csv(csv_file)
# 添加日期列
date = os.path.basename(os.path.dirname(os.path.dirname(csv_file)))
df['出发日期'] = date
# 选择指定的列
selected_columns = [
'航班号', '航空公司', '出发日期', '出发时间', '到达时间',
'中转信息', 'economy_origin', '经济舱餐食信息', '经济舱座椅间距', '出发延误时间'
]
df = df[selected_columns]
# 重命名 'economy_origin' 为 '票价'
df = df.rename(columns={'economy_origin': '票价'})
all_dfs.append(df)
# 合并所有数据框
merged_df = pd.concat(all_dfs, ignore_index=True)
# 保存为Excel文件
merged_df.to_excel(output_xlsx, index=False, engine='openpyxl')
# 设置日期范围
start_date = datetime(2024, 10, 22)
end_date = datetime(2024, 11, 1)
# 设置输入和输出文件夹路径
input_base_path = "D:\\college\\SE2\\Ctrip-Crawler-main\\Ctrip-Crawler-main"
output_folder = "D:\\college\\SE2\\Ctrip-Crawler-main\\Ctrip-Crawler-main\\xlsx_output"
# 确保输出文件夹存在
if not os.path.exists(output_folder):
os.makedirs(output_folder)
# 用于存储同一始发地和目的地的CSV文件
route_files = {}
current_date = start_date
while current_date <= end_date:
folder_name = current_date.strftime("%Y-%m-%d")
folder_path = os.path.join(input_base_path, folder_name, "2024-10-22")
if os.path.exists(folder_path):
for file_name in os.listdir(folder_path):
if file_name.endswith('.csv'):
csv_path = os.path.join(folder_path, file_name)
route = get_departure_destination(file_name)
if route not in route_files:
route_files[route] = []
route_files[route].append(csv_path)
current_date += timedelta(days=1)
# 合并并保存每个路线的文件
for route, files in route_files.items():
output_xlsx = os.path.join(output_folder, f"{route}.xlsx")
merge_csv_files(files, output_xlsx)
print(f"已合并并保存路线: {route} -> {output_xlsx}")
print("所有CSV文件已成功合并为XLSX文件并筛选了指定的列")
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