From efb9ec812c22536871b0ca482d4fe35710fbcb3c Mon Sep 17 00:00:00 2001 From: pv3e4i5aj Date: Tue, 5 Nov 2024 16:42:26 +0800 Subject: [PATCH] ADD file via upload --- 3rd.cpp | 139 ++++++++++++++++++++++++++++++++++++++++++++++++++++++++ 1 file changed, 139 insertions(+) create mode 100644 3rd.cpp diff --git a/3rd.cpp b/3rd.cpp new file mode 100644 index 0000000..a14b4c0 --- /dev/null +++ b/3rd.cpp @@ -0,0 +1,139 @@ +#include + +//任务三:判断 数组是否满足定义 +int main() +{ + int board0[9][9] = {{5, 3, 0, 0, 7, 0, 0, 0, 0}, + {6, 0, 0, 1, 9, 5, 0, 0, 0}, + {0, 9, 8, 0, 0, 0, 0, 6, 0}, + {8, 0, 0, 0, 6, 0, 0, 0, 3}, + {4, 0, 0, 8, 0, 3, 0, 0, 1}, + {7, 0, 0, 0, 2, 0, 0, 0, 6}, + {0, 6, 0, 0, 0, 0, 2, 8, 0}, + {0, 0, 0, 4, 1, 9, 0, 0, 5}, + {0, 0, 0, 0, 8, 0, 0, 7, 9}}; + + int board1[9][9] = {{8, 3, 0, 0, 7, 0, 0, 0, 0}, + {6, 0, 0, 1, 9, 5, 0, 0, 0}, + {0, 9, 8, 0, 0, 0, 0, 6, 0}, + {8, 0, 0, 0, 6, 0, 0, 0, 3}, + {4, 0, 0, 8, 0, 3, 0, 0, 1}, + {7, 0, 0, 0, 2, 0, 0, 0, 6}, + {0, 6, 0, 0, 0, 0, 2, 8, 0}, + {0, 0, 0, 4, 1, 9, 0, 0, 5}, + {0, 0, 0, 0, 8, 0, 0, 7, 9}}; + void Judge(int a[9][9]); + Judge(board0); + Judge(board1); +} + +void Judge(int a[9][9]) +{ + //Step1:输出待判断的矩阵 + printf("The original Sudoku matrix:\n") ; + for(int i=0;i<9;i++) + { + printf("|");//每一行的以|开始 + for(int j=0;j<9;j++) + { + printf("%d",a[i][j]); + if((j+1)%3==0) + { + printf("|");//区分3*3 + if(j==8) + { + printf("\n"); + } + } + } + if((i+1)%3==0&&i!=8) + { + printf("|----分割---|\n"); + }//每三行就换一行 + + } + + //Step2:进行是否满足定义的判断 + int judge=0;//judge作为是否满足定义的标准,为0表示满足 + //Step2-1:是否每一行不出现多次同一数字 + for(int i=0;i<9;i++) + { + int times[9]={0}; + for(int j=0;j<9;j++)//统计第i行每个数字的出现次数 + { + if(a[i][j]>=1)times[a[i][j]-1]++; + } + + for(int j=0;j<9;j++) + { + if(times[j]>1) + { + judge=1; + printf("False:Invalid initial Sudoku matrix!\n"); + printf("The number %d in the row %d has been used!\n",j+1,i+1); + break; + } + } + if(judge){break;} + } + + //Step2-2:判断是否每一列不出现多次同一数字 + if(judge==0) + { + for(int j=0;j<9;j++) + { + int times[9]={0}; + for(int i=0;i<9;i++)//统计第j列每个数字的出现次数 + { + if(a[i][j]>=1)times[a[i][j]-1]++; + } + + for(int i=0;i<9;i++) + { + if(times[i]>1) + { + judge=1; + printf("False:Invalid initial Sudoku matrix!\n"); + printf("The number %d in the col %d has been used!\n",i+1,j+1); + break; + } + } + if(judge){break;} + } + } + //Step2-3:每一块是否出现多次同一数字 + if(judge==0) + { + for(int i=0;i<3;i++) + { + for(int j=0;j<3;j++) + { + int times[9]={0}; + for(int m=3*i;m<=3*i+2;m++) + { + for(int n=3*j;n<=3*j+2;n++) + { + if(a[m][n]>=1)times[a[m][n]-1]++; + } + } + + for(int i=0;i<9;i++) + { + if(times[i]>1) + { + judge=1; + printf("False:Invalid initial Sudoku matrix!\n"); + printf("The number %d in the block %d has been used!\n",i+1,i+j+1); + break; + } + } + if(judge){break;} + } + if(judge){break;} + } + } + + if(judge==0){printf("True:Valid initial Sudoku matrix!\n") ;} + + return; +}