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@ -1,2 +1,209 @@
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# sort
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1.冒泡排序(O(n^2),n为数的个数)
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~~~
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#include<stdio.h>
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int main()
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{
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int a[100],i,j,t,n;
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scanf("%d", &n);//输入数据个数
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for(i = 1; i <= n; i ++)//输入数据
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{
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scanf("%d", &a[i]);
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}
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for(i = 1; i < n; i ++)//冒泡排序
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for(j = 1; j <= n - i; j ++)
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{
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if(a[j] < a[j + 1])//比较，交换
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{
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t = a[j];
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a[j] = a[ j + 1];
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a[j + 1] = t;
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}
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for(i = 1; i <= n; i ++)//输出
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printf("%d ", a[i]);
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}
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return 0;
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}
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~~~
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2.桶排序(时间复杂度 O(n+m)，n 为待排序的元素的个数，m 为桶的个数)
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~~~
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include<stdio.h>
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int main()
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{
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int a[11],i,j,t;
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for(i = 0; i <= 10; i ++)
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a[i]=0//初始化为0
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for(i = 0; i <= 5; i ++)//循环输入5个数
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{
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scanf("%d",&t);//把每一个数读到变量t中
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a[t]++;//进行计数
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}
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for(i = 0; i <= 10; i ++)//依次判断a[0]-a[10]
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for(j = 1; j <= a[i];j++)
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printf("%d ", i);
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return 0;
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}
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~~~
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3.快速排序(时间复杂度O(nlogn))
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~~~
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#include<stdio.h>
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int a[101], n;//定义成全局变量，方便在子函数中使用；
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void quicksort(int left, int right)
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{
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int i, j, t, temp;
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if(left > right)
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return;
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temp = a[left];//temp中存的基准数
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i = left;
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j = right;
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while(i != j)
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{
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//顺序很重要，要先从右往左找
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while(a[j] > temp && i < j)
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j --;
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//再从左往又找
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while(a[i] <= temp && i < j)
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i ++;
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//交换两个数所在数组中的位置
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if(i < j)
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{
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t = a[i];
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a[i] = a[j];
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a[j] = t;
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}
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}
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//最终将基准数归位
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a[left] = a[i];
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a[i] = temp;
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quicksort(left, i - 1);//继续处理左边的，这里是一个递归的过程
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quicksort(i + 1, right);//继续处理右边的
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}
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int main()
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{
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int j ,i, t;
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//读入数据
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scanf("%d", &n)
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for(int i = 1; i <= n; i ++)
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scanf("%d", &a[i]);
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quicksort(1,n);
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for(int i = 1; i <= n; i ++)
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printf("%d ",a[i]);
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return 0;
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}
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~~~
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4.堆排序（时间复杂度O(nlogn)）
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~~~
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#include<iostream>
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#include<algorithm>
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#include<cstring>
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using namespace std;
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const int N = 1e6+6;
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int size1=0,h[N],n,m=0,hp[N],ph[N];
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void heap_swap(int a, int b)
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{
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swap(ph[hp[a]],ph[hp[b]]);
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swap(hp[a],hp[b]);
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swap(h[a],h[b]);
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}
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void down(int u)
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{
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int t=u;
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if(u*2<=size1&&h[u*2]<h[t]) t=u*2;
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if(u*2+1<=size1&&h[u*2+1]<h[t]) t=u*2+1;
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if(u!=t)
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{
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heap_swap(u,t);
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down(t);
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}
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}
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void up(int u)
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{
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while(u/2&&h[u/2]>h[u])
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{
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heap_swap(u/2,u);
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u/=2;
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}
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}
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int main()
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{
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scanf("%d",&n);
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while(n--)
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{
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char op[10];
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int k,x;
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scanf("%s",op);
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if(!strcmp(op,"I"))
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{
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scanf("%d",&x);
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size1++;
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m++;
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ph[m]=size1,hp[size1]=m;
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h[size1]=x;
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up(size1);
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}
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else if(!strcmp(op,"PM"))printf("%d\n",h[1]);
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else if(!strcmp(op,"DM"))
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{
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heap_swap(1,size1);
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size1--;
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down(1);
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}
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else if(!strcmp(op,"D"))
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{
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scanf("%d",&k);
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k=ph[k];
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heap_swap(k,size1);
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size1--;
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down(k),up(k);
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}
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else
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{
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scanf("%d %d",&k,&x);
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k=ph[k];
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h[k]=x;
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down(k),up(k);
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}
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}
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return 0;
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}
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~~~
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归并排序（时间复杂度O(nlogn)）
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~~~
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int merge(int r[],int s[],int left,int mid,int right)
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{
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int i,j,k;
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i=left;
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j=mid+1;
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k=left;
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while((i<=mid)&&(j<=right))
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if(r[i]<=r[j])
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{
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s[k] = r[i];
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i++;
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k++;
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}
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else
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{
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s[k]=r[j];
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j++;
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k++;
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}
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while(i<=mid)
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s[k++]=r[i++];
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while(j<=right)
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s[k++]=r[j++];
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return 0;
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}
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int main()
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{
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int a[10];
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int i;
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for(i=0;i<10;i++)
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scanf("%d",&a[i]);
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merge_sort(a,a,0,9);
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for(i=0;i<10;i++)
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printf("%d ",a[i]);
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return 0;
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}
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~~~
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