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@ -1,5 +1,19 @@
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#include <stdio.h>
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5.堆排序
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5.1 描述
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(1)将初始待排序关键字序列(R1,R2….Rn)构建成大顶堆,此堆为初始的无序区;
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(2)将堆顶元素R[1]与最后一个元素R[n]交换,此时得到新的无序区(R1,R2,……Rn-1)和新的有序区(Rn),
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且满足R[1,2…n-1]<=R[n];
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(3)由于交换后新的堆顶R[1]可能违反堆的性质,因此需要对当前无序区(R1,R2,……Rn-1)调整为新堆,
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然后再次将R[1]与无序区最后一个元素交换,得到新的无序区(R1,R2….Rn-2)和新的有序区(Rn-1,Rn)。
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不断重复此过程直到有序区的元素个数为n-1,则整个排序过程完成
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5.2 复杂程度
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时间复杂度O(nlog2n)
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空间复杂度O(1)
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5.3 代码
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#include <stdio.h>
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void swap(int arr[], int a, int b)
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void swap(int arr[], int a, int b)
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{
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{
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int tmp;
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int tmp;
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@ -14,21 +28,21 @@ void heapify(int tree[], int n, int i)
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{
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{
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return;
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return;
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}
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}
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int max = i;//<EFBFBD><EFBFBD><EFBFBD>踸<EFBFBD>ڵ<EFBFBD>Ϊ<EFBFBD><EFBFBD><EFBFBD>ֵ
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int max = i;//假设父节点为最大值
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int c1 = 2 * i + 1;
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int c1 = 2 * i + 1;
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int c2 = 2 * i + 2; //<EFBFBD><EFBFBD><EFBFBD>ӽ<EFBFBD><EFBFBD><EFBFBD><EFBFBD>±<EFBFBD>Ϊ2i + 1, <20>Һ<EFBFBD><D2BA>ӽ<EFBFBD><D3BD><EFBFBD><EFBFBD>±<EFBFBD>Ϊ2i + 2
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int c2 = 2 * i + 2; //左孩子结点的下标为2i + 1, 右孩子结点的下标为2i + 2
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if (c1 < n && tree[c1] > tree[max])
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if (c1 < n && tree[c1] > tree[max])
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{//<EFBFBD><EFBFBD><EFBFBD>ӵ<EFBFBD><EFBFBD>±<EFBFBD>ҪС<EFBFBD><EFBFBD><EFBFBD>ܽ<EFBFBD><EFBFBD><EFBFBD><EFBFBD>
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{//左孩子的下标要小于总结点数
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max = c1;//<EFBFBD><EFBFBD><EFBFBD>ϴ<EFBFBD>ֵ<EFBFBD>Ľ<EFBFBD><EFBFBD><EFBFBD>±<EFBFBD><EFBFBD>¼<EFBFBD><EFBFBD><EFBFBD><EFBFBD>
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max = c1;//将较大值的结点下标记录下来
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}
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}
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if (c2 < n && tree[c2] > tree[max])
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if (c2 < n && tree[c2] > tree[max])
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{
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{
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max = c2;//<EFBFBD><EFBFBD><EFBFBD>ϴ<EFBFBD>ֵ<EFBFBD>Ľ<EFBFBD><EFBFBD><EFBFBD>±<EFBFBD><EFBFBD>¼<EFBFBD><EFBFBD><EFBFBD><EFBFBD>
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max = c2;//将较大值的结点下标记录下来
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}
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}
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if (max != i)
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if (max != i)
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{//<EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD>ֵ<EFBFBD><EFBFBD><EFBFBD>Ǹ<EFBFBD><EFBFBD>ڵ<EFBFBD>
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{//如果最大值不是根节点
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swap(tree, max, i);//<EFBFBD><EFBFBD><EFBFBD><EFBFBD>tree[max]<5D><>tree[i]<5D><>ֵ
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swap(tree, max, i);//交换tree[max]和tree[i]的值
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heapify(tree, n, max);//max<EFBFBD><EFBFBD><EFBFBD>Ǻ<EFBFBD><EFBFBD>ӽ<EFBFBD><EFBFBD><EFBFBD>±<EFBFBD>
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heapify(tree, n, max);//max就是孩子结点下标
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}
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}
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}
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}
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@ -48,7 +62,7 @@ void heapify_sort(int tree[], int n)
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build_heapify(tree, n);
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build_heapify(tree, n);
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int tmp = tree[0];
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int tmp = tree[0];
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for (int i = n - 1; i >= 0; i--)
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for (int i = n - 1; i >= 0; i--)
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{//<EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD>һ<EFBFBD><EFBFBD><EFBFBD><EFBFBD>㿪ʼ
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{//从最后一个结点开始
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swap(tree, i, 0);
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swap(tree, i, 0);
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heapify(tree, i, 0);
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heapify(tree, i, 0);
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}
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}
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@ -57,14 +71,14 @@ void heapify_sort(int tree[], int n)
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int main(){
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int main(){
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int tree[] = { 22, 34, 3, 32, 82, 55, 89, 50, 37, 5, 64, 35, 9, 70 };
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int tree[] = { 22, 34, 3, 32, 82, 55, 89, 50, 37, 5, 64, 35, 9, 70 };
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int n = 14;
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int n = 14;
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printf("ԭ<EFBFBD><EFBFBD><EFBFBD><EFBFBD>Ϊ:");
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printf("原数组为:");
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for (int i = 0; i < n; i++)
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for (int i = 0; i < n; i++)
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{
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{
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printf("%d ", tree[i]);
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printf("%d ", tree[i]);
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}
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}
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printf("\n");
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printf("\n");
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heapify_sort(tree, n);
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heapify_sort(tree, n);
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printf("<EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD>Ϊ<EFBFBD><EFBFBD>");
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printf("经过堆排序后的数组为:");
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for (int i = 0; i < n; i++)
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for (int i = 0; i < n; i++)
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{
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{
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printf("%d ", tree[i]);
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printf("%d ", tree[i]);
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@ -73,3 +87,5 @@ int main(){
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return 0;
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return 0;
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}
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}
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5.4 运行时间
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0.02498s
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