1 #5

Merged
p2i3t8vuh merged 1 commits from 阉割版程序 into master 2 years ago

28
.vscode/tasks.json vendored

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{
"tasks": [
{
"type": "cppbuild",
"label": "C/C++: gcc.exe 生成活动文件",
"command": "C:\\mingw64\\bin\\gcc.exe",
"args": [
"-fdiagnostics-color=always",
"-g",
"${file}",
"-o",
"${fileDirname}\\${fileBasenameNoExtension}.exe"
],
"options": {
"cwd": "${fileDirname}"
},
"problemMatcher": [
"$gcc"
],
"group": {
"kind": "build",
"isDefault": true
},
"detail": "调试器生成的任务。"
}
],
"version": "2.0.0"
}

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#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#define MAX_LEN 10 // 字符串最大长度
#define STU_NUM 30 // 最多的学生人数
#define COURSE_NUM 6 // 最多的考试科目数
typedef struct student
{
long num; // 每个学生的学号
char name[MAX_LEN]; // 每个学生的姓名
float score[COURSE_NUM]; // 每个学生COURSE_NUM门功课的成绩
float sum; // 每个学生的总成绩
float aver; // 每个学生的平均成绩
}STU;
int Menu(void);
void ReadScore(STU stu[], int n, int m);
void AverSumofEveryStudent(STU stu[], int n, int m);
int main(void)
{
char ch;
int n = 0, m = 0;
STU stu[STU_NUM];
printf("Input student number(n<%d):", STU_NUM);
scanf("%d", &n);
printf("Input course number(m<=%d):",COURSE_NUM);
scanf("%d", &m);
while (1)
{
ch = Menu(); // 显示菜单,并读取用户输入
switch (ch)
{
case 1:ReadScore(stu, n, m);
break;
case 2: AverSumofEveryStudent(stu, n, m);
break;
case 0: printf("End of program!");
exit(0);
default:printf("Input error!");
}
}
return 0;}
// 函数功能:显示菜单并获得用户键盘输入的选项
int Menu(void)
{
int itemSelected;
printf("Management for Students' scores\n");
printf("1.Input record\n");
printf("2.Calculate total and average score of every course\n");
printf("0.Exit\n");
printf("Please Input your choice:");
scanf("%d", &itemSelected); // 读入用户输入
return itemSelected;
}
// 函数功能输入n个学生的m门课成绩
void ReadScore(STU stu[], int n, int m)
{
int i, j;
printf("Input student's ID, name and score:\n");
/* ---------- begain ---------- */
for(i=0;i<n;i++)
{scanf("%ld%s",&stu[i].num,stu[i].name);
for (j=0; j<m; j++)
scanf("%f",&stu[i].score[j]);
}
/* ----------- end ----------- */
}
// 函数功能:计算每个学生各门课程的总分和平均分
void AverSumofEveryStudent(STU stu[], int n, int m)
{
int i, j;
for (i=0; i<n; i++)
{
stu[i].sum = 0;
for (j=0; j<m; j++)
{
stu[i].sum = stu[i].sum + stu[i].score[j];
}
stu[i].aver = m>0 ? stu[i].sum / m : -1;
printf("student %d: sum = %.0f, aver = %.0f\n",
i+1, stu[i].sum, stu[i].aver);
}
}
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