Update code.py

code.py

@@ -17,37 +17,32 @@ def TakeRoll():
             ins_sheet.cell(row=i, column=3).value = 0
             i += 1
         book.save(filename='sample.xlsx')
-    else:
+        return stu, idx
+    else: #学生表中含有已创建的SCredit列
         max = 0
-        credit = ins_sheet['C']
+        credit = ins_sheet['C'] #将SCredit列存入redit数组
         i = 1
         while i <= sheet.nrows-1:
-            credit[i].value *= 2
+            credit[i].value *= 2 #将所有积分值整数化（所有非整数积分值小数部分均为0.5）
             i += 1
         i = 1
         while i <= sheet.nrows-1:
             if credit[i].value > max:
                 max = credit[i].value
             i += 1
-        '''                
-        while i<=sheet.nrows:
-            if ins_sheet.cell(row=i, column=3).value > max:
-                max = ins_sheet.cell(row=i, column=3).value
-            i += 1
-        '''
-        max += 1
+        max += 1 #求出最大积分值并加1
         slct = []
         i = 1
         while i <= sheet.nrows-1:
-            credit[i].value = max - credit[i].value
+            credit[i].value = max - credit[i].value #倒转积分值，将最大的积分值置为1，其余积分依次增大
             r = 1
             while r <= int(credit[i].value):
                 slct.append(i)
-                r += 1
+                r += 1 #第i个学生倒转后的积分值即为slct数组中对应第i个学生的元素个数，和该生被选中的概率呈负相关
             i += 1
         idx = random.randint(0, len(slct)-1)
         stu = str(ins_sheet.cell(row=slct[idx]+1, column=1).value) + ins_sheet.cell(row=slct[idx]+1, column=2).value
-    return stu, slct[idx]+1
+        return stu, slct[idx]+1
 
 def CreditUpdate(stu, isInc, point):
     book = openpyxl.load_workbook(filename='sample.xlsx')
@@ -142,3 +137,4 @@ while True:
         break
 
 window.close()
+