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# -*- encoding: utf-8 -*-
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"""
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@Author: packy945
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@FileName: data.py
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@DateTime: 2023/5/11 14:36
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@SoftWare: PyCharm
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"""
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from itertools import permutations
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import random
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import tkinter as tk
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MARK = '#ff0000'
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NOMARK = '#cccccc'
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class Aexp:
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def __init__(self, a, b, c, d):
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self.Aexp_cur = 0
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self.num = 0
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self.card = [a, b, c, d]
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# print(self.card)
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self.answer = []
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self.Color = []
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self.Aexp(a, b, c, d)
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def refresh(self, a, b, c, d):
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self.Aexp_cur = 0
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self.num = 0
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self.card = [a, b, c, d]
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# print(self.card)
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self.answer = []
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self.Color = []
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self.Aexp(a, b, c, d)
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def Aexp(self, one, two, three, four):
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'''
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输入四个数，求24点
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:param one:
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:param two:
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:param three:
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:param four:
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:return: 求解24点结果。若无法得出则返回“无法求得结果”
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'''
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self.Aexp_cur = 0
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my_list = [one, two, three, four]
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result = [c for c in permutations(my_list, 4)]
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list2 = [] # 算出24的排列组合的列表
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symbols = ["+", "-", "*", "/"]
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flag = False
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for one, two, three, four in result:
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for s1 in symbols:
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for s2 in symbols:
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for s3 in symbols:
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express = ["(({0}{1}{2}){3}{4}){5}{6}".format(one[1], s1, two[1], s2, three[1], s3, four[1]),
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"({0}{1}{2}){3}({4}{5}{6})".format(one[1], s1, two[1], s2, three[1], s3, four[1]),
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"({0}{1}({2}{3}{4})){5}{6}".format(one[1], s1, two[1], s2, three[1], s3, four[1]),
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"{0}{1}(({2}{3}{4}){5}{6})".format(one[1], s1, two[1], s2, three[1], s3, four[1]),
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"{0}{1}({2}{3}({4}{5}{6}))".format(one[1], s1, two[1], s2, three[1], s3, four[1])]
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# if str(one) + str(two) + str(three) + str(four) == "8383":
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# print(express)
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for e in express:
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try:
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if round(eval(e), 6) == 24:
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e = del_parentheses(e)
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list2.append(e)
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self.Color.append([one[0], two[0], three[0], four[0]])
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flag = True
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except ZeroDivisionError:
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pass
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if flag:
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self.answer = list2
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self.num = len(list2)
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# return list3
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else:
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self.answer = ["无法得出24点"]
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self.Color.append(None)
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self.num = 0
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#删除最外层括号
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def del_parentheses(e):
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if e[0] == '(' and e[-1] == ')':
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try:
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eval(e[1:len(e)-1])
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except:
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pass
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else:
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if round(eval(e[1:len(e)-1]),6) == 24:
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return e[1:len(e)-1]
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return e
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