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斐波那契求项数和.cpp

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+//斐波拉契和//求第几项之和 
+#include<stdio.h>
+int Fibon1(int n){ 
+if (n == 1 || n == 2) { 
+ return 1; 
+} else { 
+ return Fibon1(n - 1) + Fibon1(n - 2);
+ }
+}
+int main(){ 
+int n = 0; 
+int sum = 0; 
+scanf("%d", &n); 
+for(int i=1;i<n;i++){ 
+ sum+=Fibon1(i);  
+} 
+printf("%d",sum);
+}