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@ -1073,7 +1073,7 @@ module Formula = struct
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new_eqs
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let rec solve_normalized_eq ~fuel new_eqs l1 l2 phi =
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let rec solve_normalized_lin_eq ~fuel new_eqs l1 l2 phi =
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LinArith.solve_eq l1 l2
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>>= function
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| None ->
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@ -1098,7 +1098,7 @@ module Formula = struct
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normalize it *)
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if fuel > 0 then (
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L.d_printfln "Consuming fuel solving linear equality (from %d)" fuel ;
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solve_normalized_eq ~fuel:(fuel - 1) new_eqs l (apply phi l') phi )
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solve_normalized_lin_eq ~fuel:(fuel - 1) new_eqs l (apply phi l') phi )
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else (
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(* [fuel = 0]: give up simplifying further for fear of diverging *)
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L.d_printfln "Ran out of fuel solving linear equality" ;
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@ -1154,17 +1154,17 @@ module Formula = struct
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(* no need to consume fuel here as we can only go through this branch finitely many
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times because there are finitely many variables in a given formula *)
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(* TODO: we may want to keep the "simpler" representative for [v_new] between [l1] and [l2] *)
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solve_normalized_eq ~fuel new_eqs l1 l2 phi )
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solve_normalized_lin_eq ~fuel new_eqs l1 l2 phi )
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(** an arbitrary value *)
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let base_fuel = 5
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let solve_eq new_eqs t1 t2 phi =
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solve_normalized_eq ~fuel:base_fuel new_eqs (apply phi t1) (apply phi t2) phi
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let solve_lin_eq new_eqs t1 t2 phi =
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solve_normalized_lin_eq ~fuel:base_fuel new_eqs (apply phi t1) (apply phi t2) phi
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let and_var_linarith v l (phi, new_eqs) = solve_eq new_eqs l (LinArith.of_var v) phi
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let and_var_linarith v l (phi, new_eqs) = solve_lin_eq new_eqs l (LinArith.of_var v) phi
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let rec normalize_linear_eqs ~fuel (phi0, new_eqs) =
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let* changed, phi_new_eqs' =
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@ -1214,7 +1214,7 @@ module Formula = struct
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(* NOTE: {!normalize_atom} calls {!Atom.eval}, which normalizes linear equalities so
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they end up only on one side, hence only this match case is needed to detect linear
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equalities *)
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let+ phi', new_eqs = solve_eq new_eqs l (LinArith.of_q c) phi in
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let+ phi', new_eqs = solve_lin_eq new_eqs l (LinArith.of_q c) phi in
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(true, (phi', new_eqs))
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| Some atom' ->
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Sat (false, ({phi with atoms= Atom.Set.add atom' phi.atoms}, new_eqs))
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