[sledge] Optimize and simplify Equality.solve_interp_eqs

Summary:
Due to paying closer attention to which terms are already normalized
by the accumulated solution substitution.

Reviewed By: ngorogiannis

Differential Revision: D19356323

fbshipit-source-id: e162414a0
master
Josh Berdine 5 years ago committed by Facebook Github Bot
parent ffdb429f5e
commit c8ed6dae63

@ -577,8 +577,8 @@ type 'a zom = Zero | One of 'a | Many
(* try to solve [p = q] such that [fv (p - q) ⊆ us xs] and [p - q] has at (* try to solve [p = q] such that [fv (p - q) ⊆ us xs] and [p - q] has at
most one maximal solvable subterm, [kill], where [fv kill us]; solve [p most one maximal solvable subterm, [kill], where [fv kill us]; solve [p
= q] for [kill]; extend subst mapping [kill] to the solution *) = q] for [kill]; extend subst mapping [kill] to the solution *)
let solve_poly_eq us p q subst = let solve_poly_eq us p' q' subst =
let diff = Subst.norm subst (Term.sub p q) in let diff = Term.sub p' q' in
let max_solvables_not_ito_us = let max_solvables_not_ito_us =
fold_max_solvables diff ~init:Zero ~f:(fun solvable_subterm -> function fold_max_solvables diff ~init:Zero ~f:(fun solvable_subterm -> function
| Many -> Many | Many -> Many
@ -592,16 +592,17 @@ let solve_poly_eq us p q subst =
Subst.compose1 ~key:kill ~data:keep subst Subst.compose1 ~key:kill ~data:keep subst
| Many | Zero -> None | Many | Zero -> None
let solve_interp_eq us us_xs e (cls, subst) = let solve_interp_eq us us_xs e' (cls, subst) =
[%Trace.call fun {pf} -> [%Trace.call fun {pf} ->
pf "trm: @[%a@]@ cls: @[%a@]@ subst: @[%a@]" Term.pp e pp_cls cls pf "trm: @[%a@]@ cls: @[%a@]@ subst: @[%a@]" Term.pp e' pp_cls cls
Subst.pp subst] Subst.pp subst]
; ;
( if not (Set.is_subset (Term.fv e) ~of_:us_xs) then None ( if not (Set.is_subset (Term.fv e') ~of_:us_xs) then None
else else
List.find_map cls ~f:(fun f -> List.find_map cls ~f:(fun f ->
if not (Set.is_subset (Term.fv f) ~of_:us_xs) then None let f' = Subst.norm subst f in
else solve_poly_eq us e f subst ) ) if not (Set.is_subset (Term.fv f') ~of_:us_xs) then None
else solve_poly_eq us e' f' subst ) )
|> |>
[%Trace.retn fun {pf} subst' -> [%Trace.retn fun {pf} subst' ->
pf "@[%a@]" Subst.pp_diff (subst, Option.value subst' ~default:subst) ; pf "@[%a@]" Subst.pp_diff (subst, Option.value subst' ~default:subst) ;
@ -627,12 +628,9 @@ let rec solve_interp_eqs us us_xs (cls, subst) =
let trm' = Subst.norm subst trm in let trm' = Subst.norm subst trm in
match classify trm' with match classify trm' with
| Interpreted -> ( | Interpreted -> (
match solve_interp_eq us us_xs trm' (cls', subst) with match solve_interp_eq us us_xs trm' (cls, subst) with
| None -> ( | Some subst -> solve_interp_eqs_ cls' (cls, subst)
match solve_interp_eq us us_xs trm' (cls, subst) with | None -> solve_interp_eqs_ (trm' :: cls') (cls, subst) )
| None -> solve_interp_eqs_ (trm' :: cls') (cls, subst)
| Some subst -> solve_interp_eqs_ cls' (cls, subst) )
| Some subst -> solve_interp_eqs_ cls' (cls, subst) )
| _ -> solve_interp_eqs_ (trm' :: cls') (cls, subst) ) | _ -> solve_interp_eqs_ (trm' :: cls') (cls, subst) )
in in
let cls', subst' = solve_interp_eqs_ [] (cls, subst) in let cls', subst' = solve_interp_eqs_ [] (cls, subst) in

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