vault backup: 2025-12-29 20:51:48

pull/5/head
王轲楠 3 months ago
parent 4bd3023f9b
commit e1808b06f0

@ -120,4 +120,6 @@
\underline{\qquad\qquad\qquad\qquad}.
$$
---
设$A=\begin{bmatrix}1 & -1 & 0 & -1 \\ 1 & 1 & 0 & 3 \\ 2 & 1 & 2 & 6\end{bmatrix},B=\begin{bmatrix}1 & 0 & 1 & 2 \\ 1 & -1 & a & a-1 \\ 2 & -3 & 2 & -2\end{bmatrix}$,向量$\alpha=\begin{bmatrix}0\\2\\3\end{bmatrix},\beta=\begin{bmatrix}1\\0\\-1\end{bmatrix}$.
(1)证明:方程组$Ax=\alpha$的解均为方程组$Bx=\beta$的解;
(2)若方程组$Ax=\alpha$与方程组$Bx=\beta$不同解,求$a$的值.

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