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17 lines
425 B
17 lines
425 B
2 years ago
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//3 函数功能：计算每门课程的总分和平均分
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void AverSumofEveryCourse(STU stu[], int n, int m)
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{
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int i, j;
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float sum[COURSE_NUM], aver[COURSE_NUM];
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for (j=0; j<m; j++)
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{
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sum[j] = 0;
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for (i=0; i<n; i++)
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{
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sum[j] += stu[i].score[j];
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}
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aver[j]=sum[j]/i;
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printf("student %d: sum = %.0f, aver = %.0f\n",
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j+1, sum[j], aver[j]);
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}
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}
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