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120 lines
2.7 KiB
120 lines
2.7 KiB
#include <stdio.h>
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// 输出矩阵的格式化结果
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void printarr(int arr[9][9])
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{
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int i,j,k,n;
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for(n=0;n<=6;n=n+3)
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{
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printf("|-----------------------|\n") ;
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for(i=n;i<=n+2;i++)
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{
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for(k=0;k<=6;k=k+3)
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{
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printf("|");
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for(j=k;j<=k+2;j++)
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{
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printf(" %d",arr[i][j]);
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}
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printf(" ");
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}
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printf("|\n");
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}
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}
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printf("|-----------------------|\n") ;
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}
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const char* checkSudoku(int matrix[9][9])
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{
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// 检查每一行
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for (int i = 0; i < 9; i++)
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{
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int seen[10] = {0};
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for (int j = 0; j < 9; j++)
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{
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int num = matrix[i][j];
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if (num != 0)
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{
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if (seen[num] != 0)
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{
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printf("False:Invalid initial Sudoku matrix!\nThe number %d in the row %d has been used!",num,i+1);
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return 0;
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}
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seen[num] = 1;
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}
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}
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}
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// 检查每一列
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for (int j = 0; j < 9; j++)
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{
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int seen[10] = {0};
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for (int i = 0; i < 9; i++)
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{
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int num = matrix[i][j];
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if (num != 0)
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{
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if (seen[num] != 0)
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{
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printf("False:Invalid initial Sudoku matrix!\nThe number %d in the col %d has been used!",num,j+1);
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return 0;
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}
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seen[num] = 1;
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}
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}
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}
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// 检查每个 3x3 子矩阵
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for (int block = 0; block < 9; block++)
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{
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int seen[10] = {0};
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int startRow = (block / 3) * 3;
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int startCol = (block % 3) * 3;
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for (int i = startRow; i < startRow + 3; i++)
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{
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for (int j = startCol; j < startCol + 3; j++)
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{
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int num = matrix[i][j];
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if (num != 0)
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{
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if (seen[num] != 0)
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{
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printf("False:Invalid initial Sudoku matrix!\nThe number %d in the block %d has been used!",num,block+1);
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return 0;
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}
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seen[num] = 1;
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}
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}
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}
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}
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return "True:Valid initial Sudoku matrix!";
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}
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int main() {
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int sudokuMatrix[9][9] = {
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{3, 3, 0, 0, 7, 0, 0, 0, 0},
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{6, 0, 0, 1, 9, 5, 0, 0, 0},
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{0, 9, 8, 0, 0, 0, 0, 6, 0},
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{8, 0, 0, 0, 6, 0, 0, 0, 3},
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{4, 0, 0, 8, 0, 3, 0, 0, 1},
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{7, 0, 0, 0, 2, 0, 0, 0, 6},
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{0, 6, 0, 0, 0, 0, 2, 8, 0},
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{0, 0, 0, 4, 1, 9, 0, 0, 5},
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{0, 0, 0, 0, 8, 0, 0, 7, 9}
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};
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// 输出原始数独矩阵
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printf("The original Sudoku matrix: \n");
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printarr(sudokuMatrix);
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// 判断数独矩阵是否合法
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const char* result = checkSudoku(sudokuMatrix);
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printf("%s\n", result);
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return 0;
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}
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