Add task4_pro.cpp

main
pv3e4i5aj 1 week ago
parent 86d7ae55fd
commit 625d6283ee

@ -0,0 +1,104 @@
#include <stdio.h>
#include <ctime>
#include <arm_neon.h> //启用 NEON 指令
#include <stdlib.h>
#define M 1000
#define N 1021
#define Q 1000
//A(M*N),B(N*Q),C(M*Q),transposed(Q*N)对于矩阵维度的说明
void transposeMatrix(float** matrix, float** transposed) {
for (int i = 0; i < N; i++) {
for (int j = 0; j < Q; j++) {
transposed[j][i] = matrix[i][j];
}
}
}
void matmul(float** A, float** B, float** C) {
for (int i = 0; i < M; i++) {
for (int j = 0; j < Q; j++) {
float sum = 0.0f;
for (int k = 0; k < N; k += 4)
{
float32x4_t vecA, vecB, vecC;
if (k + 4 <= N)
{
// 加载A和B的4个元素进行向量化计算
vecA = vld1q_f32(&A[i][k]);
vecB = vld1q_f32(&B[j][k]);
// 向量化乘法并累加结果
vecC = vmulq_f32(vecA, vecB);
sum += vgetq_lane_f32(vecC, 0) + vgetq_lane_f32(vecC, 1) +
vgetq_lane_f32(vecC, 2) + vgetq_lane_f32(vecC, 3);
}
else
{
// 处理剩余的元素
for (int m = k; m < N; m++)
{
sum += A[i][m] * B[j][m];
}
}
}
C[i][j] = sum;
}
}
}
int main() {
srand(time(NULL));
float** A = (float**)malloc(M * sizeof(float*));
float** B = (float**)malloc(N * sizeof(float*));
float** C = (float**)malloc(M * sizeof(float*));
float** transposed = (float**)malloc(Q * sizeof(float*));
for (int i = 0; i < M; i++) {
A[i] = (float*)malloc(N * sizeof(float));
C[i] = (float*)malloc(Q * sizeof(float));
}
for (int i = 0; i < N; ++i)
{
B[i] = (float*)malloc(Q * sizeof(float));
}
for (int i = 0; i < Q; ++i)
{
transposed[i] = (float*)malloc(N * sizeof(float));
}
// 初始化矩阵数据
for (int i = 0; i < M; i++) {
for (int j = 0; j < N; j++) {
A[i][j] = (float)(rand() % 100) / 100.0f;
}
}
for (int i = 0; i < N; i++) {
for (int j = 0; j < Q; j++) {
B[i][j] = (float)(rand() % 100) / 100.0f;
}
}
transposeMatrix(B, transposed);
clock_t start = clock();
matmul(A, transposed, C);
clock_t end = clock();
// 计算并输出矩阵乘法的时间
double multiply_time_spent = double(end - start) / CLOCKS_PER_SEC;
printf("使用优化的向量乘法:\n当矩阵A的维度为%d*%d,矩阵B的维度为%d*%d时优化的向量乘法时间%lf秒\n", M,N,N,Q,multiply_time_spent);
// 释放动态分配的内存
for (int i = 0; i < M; ++i) {
free(A[i]);free(C[i]);
}
for (int i = 0; i < N ;++i) {
free(B[i]);
}
for (int i = 0; i < Q ;++i) {
free(transposed[i]);
}
free(A); free(B); free(C);free(transposed);
}
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