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@ -0,0 +1,69 @@
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#include <stdio.h>
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#include <ctime>
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#include <stdlib.h>
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#define M 1000
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#define N 1021
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#define Q 1000
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//A(M*N),B(N*Q),C(M*Q)对于矩阵维度的说明
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void matmul(float** A, float** B, float** C)
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{
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for (int i = 0; i < M; ++i)
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{
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for (int j = 0; j < Q; ++j)
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{
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C[i][j] = 0;
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for (int k = 0; k < N; ++k)
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{
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C[i][j] += A[i][k] * B[k][j];
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}
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}
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}
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}
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int main()
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{
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srand(time(NULL));
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// 分配矩阵内存
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float** A = (float**)malloc(M * sizeof(float*));
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float** B = (float**)malloc(N * sizeof(float*));
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float** C = (float**)malloc(M * sizeof(float*));
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for (int i = 0; i < M; ++i)
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{
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A[i] = (float*)malloc(N * sizeof(float));
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C[i] = (float*)malloc(Q * sizeof(float));
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}
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for (int i = 0; i < N; ++i)
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{
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B[i] = (float*)malloc(Q * sizeof(float));
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}
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// 初始化矩阵数据
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for (int i = 0; i < M; i++) {
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for (int j = 0; j < N; j++) {
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A[i][j] = (float)(rand() % 100) / 100.0f;
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}
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}
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for (int i = 0; i < N; i++) {
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for (int j = 0; j < Q; j++) {
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B[i][j] = (float)(rand() % 100) / 100.0f;
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}
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}
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clock_t start = clock();
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matmul(A, B, C);
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clock_t end = clock();
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// 计算并输出向量乘法的时间
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double multiply_time_spent = double(end - start) / CLOCKS_PER_SEC;
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printf("使用基础的向量乘法:\n当矩阵A的维度为%d*%d,矩阵B的维度为%d*%d时,初始向量乘法时间:%lf秒\n",M,N,N,Q,multiply_time_spent);
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// 释放动态分配的内存
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for (int i = 0; i < M; ++i) {
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free(A[i]);free(C[i]);
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}
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for (int i = 0; i < N ;++i) {
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free(B[i]);
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}
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free(A); free(B); free(C);
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}
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