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p5gq69iu7 6 months ago
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wzy.py
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# 1、画棋盘，初始化棋盘
from turtle import *
screensize()
tracer(0)
for i in range(15):#画横向
penup()
goto(-280,-280+i*40)
pendown()
fd(560)
left(90)
for i in range(15):#画竖向
penup()
goto(-280+i*40,-280)
pendown()
fd(560)
penup() #画标点
goto(0,0)
dot()
goto(160,160)
dot()
goto(-160,160)
dot()
goto(160,-160)
dot()
goto(-160,-160)
dot()
#如果要使用列表创建一个二维数组，可以使用生成器来辅助实现。
#棋盘上每一个点初始值为0
arr=[[0 for i in range(15)] for j in range(15)]
# 3、判断4个方向是否连成五个子
def fun_null(x,y):
return ;
def black_is_end(i,j):
global arr
for m in range(11): #竖向
if arr[m][j]==1 and arr[m+1][j]==1 and arr[m+2][j]==1 and \
arr[m+3][j]==1 and arr[m+4][j]==1:
print("游戏结束，黑子胜利！")
onscreenclick(fun_null)
for m in range(11): #横向
if arr[i][m]==1 and arr[i][m+1]==1 and arr[i][m+2]==1 and \
arr[i][m+3]==1 and arr[i][m+4]==1:
print("游戏结束，黑子胜利！")
onscreenclick(fun_null)
if i<=j: #\向
m=j-i
for k in range(m,11):
if arr[k-m][k]==1 and arr[k-m+1][k+1]==1 and arr[k-m+2][k+2]==1 and \
arr[k-m+3][k+3]==1 and arr[k-m+4][k+4]==1:
print("游戏结束，黑子胜利！")
onscreenclick(fun_null)
if i>j: #\向
m=i-j
for k in range(m,11):
if arr[k][k-m]==1 and arr[k+1][k-m+1]==1 and arr[k+2][k-m+2]==1 and \
arr[k+3][k-m+3]==1 and arr[k+4][k-m+4]==1:
print("游戏结束，黑子胜利！")
onscreenclick(fun_null)
n=i+j #/向
if n<=14:
for k in range(0,n-4):
if arr[k][n-k]==1 and arr[k+1][n-k-1]==1 and arr[k+2][n-k-2]==1 and \
arr[k+3][n-k-3]==1 and arr[k+4][n-k-4]==1:
print("游戏结束，黑子胜利！")
onscreenclick(fun_null)
if n>14:
for v in range(n-14,11):
if arr[v][n-v]==1 and arr[v+1][n-v-1]==1 and arr[v+2][n-v-2]==1 and \
arr[v+3][n-v-3]==1 and arr[v+4][n-v-4]==1:
print("游戏结束，黑子胜利！")
onscreenclick(fun_null)
def white_is_end(i,j):
global arr
for m in range(11): #竖向
if arr[m][j]==-1 and arr[m+1][j]==-1 and arr[m+2][j]==-1 and \
arr[m+3][j]==-1 and arr[m+4][j]==-1:
print("游戏结束，白子胜利！")
onscreenclick(fun_null)
for m in range(11): #横向
if arr[i][m]==-1 and arr[i][m+1]==-1 and arr[i][m+2]==-1 and \
arr[i][m+3]==-1 and arr[i][m+4]==-1:
print("游戏结束，白子胜利！")
onscreenclick(fun_null)
if i<=j: #\向
m=j-i
for k in range(m,11):
if arr[k-m][k]==-1 and arr[k-m+1][k+1]==-1 and arr[k-m+2][k+2]==-1 and \
arr[k-m+3][k+3]==-1 and arr[k-m+4][k+4]==-1:
print("游戏结束，白子胜利！")
onscreenclick(fun_null)
if i>j: #\向
m=i-j
for k in range(m,11):
if arr[k][k-m]==-1 and arr[k+1][k-m+1]==-1 and arr[k+2][k-m+2]==-1 and \
arr[k+3][k-m+3]==-1 and arr[k+4][k-m+4]==-1:
print("游戏结束，白子胜利！")
onscreenclick(fun_null)
n=i+j #/向
if n<=14:
for k in range(0,n-4):
if arr[k][n-k]==-1 and arr[k+1][n-k-1]==-1 and arr[k+2][n-k-2]==-1 and \
arr[k+3][n-k-3]==-1 and arr[k+4][n-k-4]==-1:
print("游戏结束，白子胜利！")
onscreenclick(fun_null)
if n>14:
for v in range(n-14,11):
if arr[v][n-v]==-1 and arr[v+1][n-v-1]==-1 and arr[v+2][n-v-2]==-1 and \
arr[v+3][n-v-3]==-1 and arr[v+4][n-v-4]==-1:
print("游戏结束，白子胜利！")
onscreenclick(fun_null)
# 2、鼠标事件，点击落子
turn=0 #记录该哪方落子
def funclick(x,y):
global turn
global arr
if turn==0: #黑子先下1
for i in range(15):
Y=280-i*40
for j in range(15):
X=-280+j*40 #棋盘上的整点
if abs(X-x)<20 and abs(Y-y)<20 and arr[i][j]==0:
arr[i][j]=1
goto(X,Y)
dot(20)
turn=1 #交替下子
black_is_end(i,j)
if turn==1: #白子-1
for i in range(15):
Y=280-i*40
for j in range(15):
X=-280+j*40 #棋盘上的整点
if abs(X-x)<20 and abs(Y-y)<20 and arr[i][j]==0:
arr[i][j]=-1
goto(X+10,Y)
pendown()
circle(10)
penup()
turn=0 #交替下子
white_is_end(i,j)
onscreenclick(funclick)
done()
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