parent
375c0440ec
commit
7b16abeee3
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# -*- encoding: utf-8 -*-
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from head import *
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from NODE import *
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from SOLVE import *
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solve = Solve()
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N = Node()
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class Ways:
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def __init__(self):
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self.user_way = []#记录用户路径
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self.user_cur = 0#记录用户所在点
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self.user_flag = set()#记录用户已经过的点
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def clear(self):
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self.user_flag.clear()
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self.user_way.clear()
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self.user_cur = 0
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self.auto_ways()
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def check_user_best2(self): # 检查用户路径是不是最佳路径
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solve.node_dfs()#遍历计算最优路径
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if not len(self.user_way) == len(solve.ans):# 节点个数不一样肯定不匹配
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return 0
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dis_user = 0
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dis_ans = 0
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num = len(self.user_way)
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for i in range(num - 1):#计算两条路径的长度
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dis_user += d.Edges[G.node_edge(self.user_way[i], self.user_way[i + 1])][6]
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dis_ans += d.Edges[G.node_edge(solve.ans[i], solve.ans[i + 1])][6]
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if dis_ans == dis_user: # 用户路径长度与最短路径长度相同,用户路径是最短路
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return 1
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return 0# 匹配失败,不是最短路
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def check_user_best(self): # 检查用户路径是不是最佳路径
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# global user_way
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# global ans
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solve.node_dfs()
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# 长度不一样肯定不匹配
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if not len(self.user_way) == len(solve.ans):
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return 0
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dis_user = 0
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dis_ans = 0
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# print(user_way)
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# print(ans)
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num = len(self.user_way)
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for i in range(num - 1):
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dis_user += d.Edges[G.node_edge(self.user_way[i], self.user_way[i + 1])][6]
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dis_ans += d.Edges[G.node_edge(solve.ans[i], solve.ans[i + 1])][6]
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return dis_ans, dis_user
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# if dis_ans == dis_user: # 匹配成功,用户路径是最短路
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# return 1
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# # 匹配失败,不是最短路
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# return 0
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def show_best_ans(self, top, best, user):
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lab1 = tk.Label(top, text="最短路径:", fg=BLACK, font=('微软雅黑', 20))
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b_way = ""
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for a in solve.ans:
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b_way += d.Nodes[a][1]
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b_way += "->"
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b_way += d.Nodes[0][1]
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y0 = 0.05
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lab2 = tk.Label(top, text=f"{b_way}", bg=BLUE, fg=BLACK, font=('微软雅黑', 12), wraplength=200, justify='left')
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lab1.place(relx=0.1, rely=0.50 + y0, width=150, height=30)
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lab2.place(relx=0.4, rely=0.45 + y0, width=200, height=100)
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lab2 = tk.Label(top, text=f"最佳路径总成本:{best}\n用户路径总成本:{user}", bg=BLUE, fg=BLACK, font=('微软雅黑', 12), wraplength=200, justify='left')
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lab2.place(relx=0.4, rely=0.7 + y0, width=200, height=100)
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def show_BEST(self):
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top = Toplevel(root, width=500, height=500)
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top.title('判断路径是否为最短路径')# 弹出一个新的窗口来显示判断结果
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lab1 = tk.Label(top, text="用户路径:", fg=BLACK, font=('微软雅黑', 20))# 显示当前用户路径信息
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u_way = ""#生成用户路径
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for a in self.user_way:
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u_way += d.Nodes[a][1]
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u_way += "->"
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u_way += d.Nodes[0][1]#回到起始点
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y0 = 0.05
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lab2 = tk.Label(top, text=f"{u_way}", bg=BLUE, fg=BLACK, font=('微软雅黑', 12), wraplength=200,justify='left')
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lab1.place(relx=0.1, rely=0.10 + y0, width=150, height=30)
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lab2.place(relx=0.4, rely=0.05 + y0, width=200, height=100)
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best, user = self.check_user_best()# 计算最优路径与用户路径的总花费
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if best == user:# 如果最优路径与用户路径的总花费相等,则说明用户路径是最短路径
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result = "用户路径是最短路径"
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else:#否则说明用户路径不是最短路径
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result = "用户路径不是最短路径"
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# 如果用户路径不是最短路径,则增加一个"显示最佳路径"的按钮
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B = tk.Button(top, text="显示最佳路径", command=lambda: self.show_best_ans(top, best, user))
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B.place(relx=0.6, rely=0.30 + y0, width=100, height=50)
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lab = tk.Label(top, text=f"{result}", bg=BLUE, fg=BLACK, font=('微软雅黑', 12), wraplength=200, justify='left')
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lab.place(relx=0.1, rely=0.3 + y0, width=200, height=50)
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def check_user_greey(self): # 检查用户路径是不是贪心路径,不是的话返回错误点
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solve.node_greedy()# 计算贪心路径
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if not len(self.user_way) == len(solve.ans):# 路径长度不一样肯定不匹配,直接返回
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self.auto_ways()
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return
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num = len(self.user_way)
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for i in range(num):#逐个节点进行匹配
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if not self.user_way[i] == solve.ans[i]:# 若第i位匹配失败则返回i
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return i
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return -1#-1表示是贪心路径
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def show_greddy_ans(self, top):
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lab1 = tk.Label(top, text="最短路径:", fg=BLACK, font=('微软雅黑', 20))
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b_way = ""
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for a in solve.ans:
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b_way += d.Nodes[a][1]
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b_way += "->"
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b_way += d.Nodes[0][1]
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y0 = 0.05
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lab2 = tk.Label(top, text=f"{b_way}", bg=BLUE, fg=BLACK, font=('微软雅黑', 12), wraplength=200, justify='left')
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lab1.place(relx=0.1, rely=0.50 + y0, width=150, height=30)
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lab2.place(relx=0.4, rely=0.45 + y0, width=200, height=100)
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def show_GREDDY(self):
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top = Toplevel(root, width = 500, height = 500)
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top.title('判断路径是否为贪心路径')# 新建一个窗口来显示判断路径是否为贪心路径的结果
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lab1 = tk.Label(top, text="用户路径:", fg=BLACK, font=('微软雅黑', 20))
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u_way = ""# 显示用户路径
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for a in self.user_way:
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u_way += d.Nodes[a][1]
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u_way += "->"
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u_way += d.Nodes[0][1]
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y0 = 0.05
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lab2 = tk.Label(top, text=f"{u_way}", bg=BLUE, fg=BLACK, font=('微软雅黑', 12), wraplength=200,justify='left')
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lab1.place(relx=0.1, rely=0.10 + y0, width=150, height=30)
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lab2.place(relx=0.4, rely=0.05 + y0, width=200, height=100)
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# 逐个节点比较用户路径是否为贪心路径
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g = self.check_user_greey()
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if g == -1:#如果用户路径是贪心路径则显示
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result = '用户路径是贪心路径'
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else:# 若用户路径不是贪心路径,则显示在第几步时选择出错,并将该次选择的正确选择与用户实际选择显示出来
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result = '用户路径不是贪心路径'
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result2 = '用户路径'+d.Nodes[self.user_way[g-1]][1]+'->'+d.Nodes[self.user_way[g]][1]+' 成本为%d\n'%d.Edges[G.node_edge(self.user_way[g-1],self.user_way[g])][6]
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result2 += '贪心路径' + d.Nodes[solve.ans[g - 1]][1] + '->' + d.Nodes[solve.ans[g]][1] + ' 成本为%d\n' % d.Edges[G.node_edge(solve.ans[g-1],solve.ans[g])][6]
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lab = tk.Label(top, text=result2, bg=BLUE, fg=BLACK, font=('微软雅黑', 12), wraplength=200, justify='left')
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lab.place(relx=0.1, rely=0.5 + y0, width=250, height=100)
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lab = tk.Label(top, text=result, bg=BLUE, fg=BLACK, font=('微软雅黑', 12), wraplength=250, justify='left')
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lab.place(relx=0.1, rely=0.3 + y0, width=200, height=50)
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self.auto_ways()#将结果输出到输出框
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# 记录用户路径(路径操作)
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def way_mark_display(self): # 用户路径显示
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E.newedge_del_all(1)
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for w in frame_right.winfo_children():
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w.destroy()
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# 清除右侧组件
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lab = tk.Label(frame_right, text="路径操作", bg=RED, fg=BLACK, font=('微软雅黑', 20))
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lab.place(relx=0.05, rely=0.02, width=300, height=30)
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y0 = 0.1
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lab1 = tk.Label(frame_right, text="用户路径:", bg=RED, fg=BLACK, font=('微软雅黑', 12))
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self.auto_ways()
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way = ""
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for a in self.user_way:
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way += d.Nodes[a][1]
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way += "->"
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way += d.Nodes[0][1]
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lab2 = tk.Label(frame_right, text=f"{way}", bg=BLUE, fg=BLACK, font=('微软雅黑', 12), wraplength=200,
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justify='left')
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lab1.place(relx=0.1, rely=0.05 + y0, width=80, height=30)
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lab2.place(relx=0.1, rely=0.15 + y0, width=200, height=100)
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B = tk.Button(frame_right, text="清除路径", command=lambda: self.user_way_clear())
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B.place(relx=0.8, rely=0.15 + y0, width=50, height=30)
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B = tk.Button(frame_right, text="撤销", command=lambda: self.user_way_del())
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B.place(relx=0.8, rely=0.20 + y0, width=50, height=30)
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B = tk.Button(frame_right, text="检查路径", command=lambda: self.user_way_check())
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B.place(relx=0.8, rely=0.25 + y0, width=50, height=30)
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B = tk.Button(frame_right, text="判断路径是否为最短路径", command=lambda: self.user_way_best())
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B.place(relx=0.1, rely=0.30 + y0, width=200, height=30)
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B = tk.Button(frame_right, text="判断路径是否为贪心路径", command=lambda: self.user_way_greedy())
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B.place(relx=0.1, rely=0.35 + y0, width=200, height=30)
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def auto_ways(self): # 标记用户路径
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for w in d.Edges:#清空路径标记
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w[4] = 0
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for N in d.Nodes:#清空节点标记
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N[2] = 0
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for w in self.user_way:# 标记用户已选的点
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d.Nodes[w][2] = 5
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for w in range(len(self.user_way) - 1):# 标记用户经过的路径
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d.Edges[G.node_edge(self.user_way[w], self.user_way[w + 1])][4] = 1
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if len(set(self.user_way)) == len(d.Nodes):# 如果已经访问所有节点,自动回到初始节点
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d.Edges[G.node_edge(self.user_way[len(self.user_way) - 1], 0)][4] = 1
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G.draw()# 按照标记重新绘制图形
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def user_way_clear(self):
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self.user_flag.clear()
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self.user_flag.add(0)
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self.user_way.clear()
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self.user_cur = 0
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self.user_way.append(0)
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self.auto_ways()
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self.way_mark_display()
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def user_way_del(self): # 删除路径最后一步
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if len(self.user_way) <= 1:
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return
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cur = self.user_way.pop()
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self.user_cur = self.user_way[len(self.user_way) - 1]
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self.user_flag.discard(cur)
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self.auto_ways()
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self.way_mark_display()
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def way_check(self): # 检查路径是否合法
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if not len(self.user_way) == len(d.Nodes):# 若用户路径没有遍历所有节点,则不合法
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return "Error: not all nodes are traversed in the user path"
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for w in range(len(self.user_way) - 1):# 若用户路径不连通,则不合法
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if not d.Edges[G.node_edge(self.user_way[w], self.user_way[w + 1])][3] == 1:
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return "Error: user path is not connected between node {} and node {}".format(self.user_way[w], self.user_way[w + 1])
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if d.Edges[G.node_edge(0, self.user_way[len(self.user_way) - 1])][3] == 1:
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return "Valid path"
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else:# 若用户路径无法回到出发点,则不合法
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return "Error: user path does not return to the starting point"
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def user_way_check(self): # 检查路径是否合法并弹窗
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check = self.way_check()
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if not check == "Valid path":
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result = tk.messagebox.askokcancel(title='结果', message = check)
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else:
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result = tk.messagebox.askokcancel(title='结果', message ='该路径合法')
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def user_way_add(self, nxt): # 用户路径操作
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# print(nxt)
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if nxt in self.user_flag:
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return
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# 看用户选择的路径是否存在
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if d.Edges[G.node_edge(self.user_cur, nxt)][3] == 1:
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# 将该点加入用户路径
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self.user_way.append(nxt)
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self.user_flag.add(nxt)
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self.user_cur = nxt
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self.way_mark_display()
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# print(user_way)
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def user_way_greedy(self): # 检查路径是否为最短路径并显示
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check = self.way_check()
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if not check == "Valid path":
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result = tk.messagebox.askokcancel(title='错误', message = check)
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return 0
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# 若路径不合法,直接弹窗并返回
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if solve.node_greedy() == -1:
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return 0
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self.show_GREDDY()
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def user_way_best(self): # 检查路径是否为最短路径并显示
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check = self.way_check()
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if not check == "Valid path":# 如果用户路径不合法,则直接返回
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tk.messagebox.askokcancel(title='错误', message = check)
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return 0
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# 若路径不合法,直接弹窗并返回
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self.show_BEST()
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if __name__ == '__main__':
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G.draw()
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# userG = USER_GREEDY()
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# userB = USER_BSET()
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W = Ways()
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W.way_mark_display()
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mainloop()
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@ -0,0 +1,41 @@
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# -*- encoding: utf-8 -*-
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# 查询城市的经纬度并存入excel中
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# 本次整体的源代码
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AK = "9AfjsK2CXGuESwSb4sF3LsGhWh999Rdd"
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import pandas as pd
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import requests
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import json
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def getPosition(address):
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url = r"http://api.map.baidu.com/place/v2/search?query={}®ion=全国&output=json&ak={}".format(
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address,
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AK # 这里是一开始截图用红色圈起来的部分,无需修改
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)
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res = requests.get(url)
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json_data = json.loads(res.text)
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if json_data["status"] == 0:
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lat = json_data["results"][0]["location"]["lat"] # 纬度
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lng = json_data["results"][0]["location"]["lng"] # 经度
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else:
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print(json_data["message"])
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return "0,0", json_data["status"]
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return lat,lng
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if __name__ == "__main__":
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res = []
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maps = ['哈尔滨市', '齐齐哈尔市', '鸡西市', '鹤岗市', '双鸭山市', '大庆市', '伊春市', '佳木斯市', '七台河市', '牡丹江市', '黑河市', '绥化市', '大兴安岭地区']
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for i in range(len(maps)):
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Name = maps[i]
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P1 = getPosition(Name)
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res.append([Name, P1[0], P1[1]])
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pd.DataFrame(res).to_excel(
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"data.xlsx",
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header=["地点", "纬度", "经度"],
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index=None,
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encoding="utf-8"
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)
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Reference in new issue