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main
pqrug8l6s 1 month ago
parent 4f3fccf24c
commit 69430d57fd

@ -0,0 +1,119 @@
#include <stdio.h>
// 输出矩阵的格式化结果
void printarr(int arr[9][9])
{
int i,j,k,n;
for(n=0;n<=6;n=n+3)
{
printf("|-----------------------|\n") ;
for(i=n;i<=n+2;i++)
{
for(k=0;k<=6;k=k+3)
{
printf("|");
for(j=k;j<=k+2;j++)
{
printf(" %d",arr[i][j]);
}
printf(" ");
}
printf("|\n");
}
}
printf("|-----------------------|\n") ;
}
const char* checkSudoku(int matrix[9][9])
{
// 检查每一行
for (int i = 0; i < 9; i++)
{
int seen[10] = {0};
for (int j = 0; j < 9; j++)
{
int num = matrix[i][j];
if (num != 0)
{
if (seen[num] != 0)
{
printf("False:Invalid initial Sudoku matrix!\nThe number %d in the row %d has been used!",num,i+1);
return 0;
}
seen[num] = 1;
}
}
}
// 检查每一列
for (int j = 0; j < 9; j++)
{
int seen[10] = {0};
for (int i = 0; i < 9; i++)
{
int num = matrix[i][j];
if (num != 0)
{
if (seen[num] != 0)
{
printf("False:Invalid initial Sudoku matrix!\nThe number %d in the col %d has been used!",num,j+1);
return 0;
}
seen[num] = 1;
}
}
}
// 检查每个 3x3 子矩阵
for (int block = 0; block < 9; block++)
{
int seen[10] = {0};
int startRow = (block / 3) * 3;
int startCol = (block % 3) * 3;
for (int i = startRow; i < startRow + 3; i++)
{
for (int j = startCol; j < startCol + 3; j++)
{
int num = matrix[i][j];
if (num != 0)
{
if (seen[num] != 0)
{
printf("False:Invalid initial Sudoku matrix!\nThe number %d in the block %d has been used!",num,block+1);
return 0;
}
seen[num] = 1;
}
}
}
}
return "True:Valid initial Sudoku matrix!";
}
int main() {
int sudokuMatrix[9][9] = {
{3, 3, 0, 0, 7, 0, 0, 0, 0},
{6, 0, 0, 1, 9, 5, 0, 0, 0},
{0, 9, 8, 0, 0, 0, 0, 6, 0},
{8, 0, 0, 0, 6, 0, 0, 0, 3},
{4, 0, 0, 8, 0, 3, 0, 0, 1},
{7, 0, 0, 0, 2, 0, 0, 0, 6},
{0, 6, 0, 0, 0, 0, 2, 8, 0},
{0, 0, 0, 4, 1, 9, 0, 0, 5},
{0, 0, 0, 0, 8, 0, 0, 7, 9}
};
// 输出原始数独矩阵
printf("The original Sudoku matrix: \n");
printarr(sudokuMatrix);
// 判断数独矩阵是否合法
const char* result = checkSudoku(sudokuMatrix);
printf("%s\n", result);
return 0;
}
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